Electrical Engineering - RLC Circuits and Resonance - Discussion

It is for internal resistance present in the inductor and capacitor.

Genrally, we solve this problem in tank circuit model
XL=2*3.14*f*L.
Xc=1/(2*3.14*f*C).

After convert all parallel networks into conductance,suceptance,admitance values
Conductance(G)=(R)/(R^2 + X^2); R=30
In this scenario internal restance present in L&C.
so we are taking suceptance(B)=(X)/(R^2 + X^2); R=30.
Y=y1 + y2 + y3 Here, Y= admitance.

Y=G1+G2 + G3 + J(BL -Bc); G1 value take restor R1=6800 OHM; G2&G3 values take R=30.

After calculation,
Y=G + J(B),
finally R=1/G,
R=18,780 OHMS.

Actually the resistance of a parallel circuit will be less than that resistor which has less resistance value).

So here R = 6800 ohms.

Internal resistance of l = 30 ohms.

And Resistance of capacitor = Very high value.

So the total resistance required of the circuit would be less than 30 ohms.

I'm not getting the right answer.

My answer is 292.6 - 1173j after adding all components in parallel and taking w=106.8k.

Should I take w=17khz ?

Please help me out. It's so much time taking.

I am getting around the same answer as you: 294.2-1174j. Even if you use w = 17 kHz (leaving out the 2*pi) you still dont get it.

I got 34.6+122.4j. Not sure how they are getting this answer.

This answer doesn't make any sense. How is the equivalent parallel resistance larger than the one resistor that is known, 6800?

If in parallel, it should be at least lower than 6800.

Consider internal resistance of coil with inductive reactance.

Z (L) =jX (L) +R (L).

And add all components in parallel now.

It's complex but you will get answer.

@Mrakovic.

Can you tell me what is Q? And by using your formula I get an answer is 18660.192 but I have a confusion this answer is right or wrong.

1/Z=(1/R)+[1/(Rw+jXl)]+[1/jXc].

Is the above equation correct or did go wrong any where, because I got totally different answer. Please help me?

We could find answer by conventional way but is there any shortcut to find quick answer as conventional way is highly time taking.

I can not understand by this above solution. I want something simple and quickly under stable method. Please provide it.