Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 7)
7.
A 6.8 k
resistor, a 7 mH coil, and a 0.02 
F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is
resistor, a 7 mH coil, and a 0.02 F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is1,878
18,780
18,750
626
Discussion:
34 comments Page 2 of 4.
DARSH said:
3 years ago
Here, we didn't find the equivalent resister of parallel circuit. Without resistor place in series with capacitor.
(1)
Sunil said:
1 decade ago
It is Resistance that has been asked for not impedance, in which case the answer should have been 29.9ohms.
Ajit Kumar said:
1 decade ago
1/(Z-30) = 1/6.8 + J*.017*0.02 + 1/(J17*7).
Now Z can be calculated in form of 1/z = x + j Y.
Rp = 1/x.
Now Z can be calculated in form of 1/z = x + j Y.
Rp = 1/x.
Muhammad said:
7 years ago
By using this equation1/Z=(1/R)2+(1/XL2-1/XC2)2 we get the answer.
(1)
Manoj patil said:
10 years ago
Please give me right solution because I got totally wrong answer.
Arunkumar said:
7 years ago
What is X value in G and J value in Y?
Please explain clearly.
Please explain clearly.
Parneet kaur said:
1 decade ago
Please explain it in detail. I am also getting wrong answer.
Bharath said:
9 years ago
Please show how to make the conversion without calculator.
Souma said:
1 decade ago
I need some quickly make out method, someone please help.
Hailemichael said:
1 decade ago
I am also getting wrong answer. Please explained briefly?
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