Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 17)
17.
In a certain series resonant circuit, VC = 125 V, VL = 125 V, and VR = 40 V. The value of the source voltage is
125 V
250 V
290 V
40 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Javaid Iqbal said:   6 years ago
In Series parallel Resonant circuits, means where circuit response is resonant (that achieve when XL = XC).

So, as per the question statement, the circuit was resonance. this is why VL^2 got canceled with Vc^2 due to the same value.

Pinki said:   1 decade ago
Under resonance inductor voltage equal to capacitor voltage. One voltage (inductor) lags the power and another (capacitor voltage) leads the power so power become zero, remains only resistive power = 40 V so simple.

DINESH said:   1 decade ago
In series resonance XL=XC.

Since it is a series circuit therefore IXL=IXC.

Hence inductive reactance and capacitive reactance will cancel out each other.

So the answer will be VS=VR=40V.

Parth said:   8 years ago
Vs = √Vr^2 + (Vl -Vc)^2).
= √(Vr^2 + 0). (Vl = Vc, Vl - Vc =0),
= √Vr^2,
= Vr,
= 40V.
(1)

Kani said:   1 decade ago
You consider a RLC circuit first elements are so the supply (sources) voltage as Vr=40.

Vaibhav ghatol said:   9 years ago
Under resonance.

Xl = xc or vl = vc and hence,
Vs = vr =40volts.
That's it.
(1)

Gnanesh said:   9 years ago
Both inductive & capacitive reactance are cancelled as both are equal.

Rajkumar said:   8 years ago
It is asking source voltage, not output voltage. So please explain this.

Rutesh said:   1 decade ago
Vs ^2 = (Vr^2 + (Vl-Vc)^2 ),

For resonance , Vl = Vc ,

So , Vs = Vr.

HajaH said:   8 years ago
Simple in series circuit reference voltage is equal to source voltage.


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