Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 17)
17.
In a certain series resonant circuit, VC = 125 V, VL = 125 V, and VR = 40 V. The value of the source voltage is
Discussion:
19 comments Page 2 of 2.
K.Gopalakrishna said:
9 years ago
In series circuit, the voltage differ.
125 - 125 - 40= negative.
125 - 125 - 40= negative.
(1)
Dharmish said:
1 decade ago
Please explain me in detail because I can't understand.
Murali said:
9 years ago
I can't understand, so can anyone help me to get it.
Ashok said:
1 decade ago
Vs^2 = (Vr^2 + (Vl^2 - Vc^2)^2)
Therefor, Vs = Vr.
Therefor, Vs = Vr.
Vadivel said:
1 decade ago
I am not cleared that problem please explain.
Nayak said:
1 decade ago
Vr=Vl-Vr
40=125-125
40=0
Answer D is correct
40=125-125
40=0
Answer D is correct
Yaswanth said:
1 decade ago
I don't understand please explain.
Amol Shirgaonkar said:
9 years ago
It is √(vr^;2+(vl-vc)^2).
HAris said:
6 years ago
Right, thanks @Parth.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers