Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 17)
17.
In a certain series resonant circuit, VC = 125 V, VL = 125 V, and VR = 40 V. The value of the source voltage is
Discussion:
19 comments Page 1 of 2.
Kani said:
1 decade ago
You consider a RLC circuit first elements are so the supply (sources) voltage as Vr=40.
Ashok said:
1 decade ago
Vs^2 = (Vr^2 + (Vl^2 - Vc^2)^2)
Therefor, Vs = Vr.
Therefor, Vs = Vr.
Nayak said:
1 decade ago
Vr=Vl-Vr
40=125-125
40=0
Answer D is correct
40=125-125
40=0
Answer D is correct
Rutesh said:
1 decade ago
Vs ^2 = (Vr^2 + (Vl-Vc)^2 ),
For resonance , Vl = Vc ,
So , Vs = Vr.
For resonance , Vl = Vc ,
So , Vs = Vr.
Vadivel said:
1 decade ago
I am not cleared that problem please explain.
Pinki said:
1 decade ago
Under resonance inductor voltage equal to capacitor voltage. One voltage (inductor) lags the power and another (capacitor voltage) leads the power so power become zero, remains only resistive power = 40 V so simple.
Dharmish said:
1 decade ago
Please explain me in detail because I can't understand.
Yaswanth said:
1 decade ago
I don't understand please explain.
DINESH said:
1 decade ago
In series resonance XL=XC.
Since it is a series circuit therefore IXL=IXC.
Hence inductive reactance and capacitive reactance will cancel out each other.
So the answer will be VS=VR=40V.
Since it is a series circuit therefore IXL=IXC.
Hence inductive reactance and capacitive reactance will cancel out each other.
So the answer will be VS=VR=40V.
Murali said:
9 years ago
I can't understand, so can anyone help me to get it.
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