Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 17)
In a certain series resonant circuit, VC = 125 V, VL = 125 V, and VR = 40 V. The value of the source voltage is
125 V
250 V
290 V
40 V
Answer: Option
No answer description is available. Let's discuss.
19 comments Page 1 of 2.

HAris said:   3 years ago
Right, thanks @Parth.

Javaid Iqbal said:   3 years ago
In Series parallel Resonant circuits, means where circuit response is resonant (that achieve when XL = XC).

So, as per the question statement, the circuit was resonance. this is why VL^2 got canceled with Vc^2 due to the same value.

HajaH said:   5 years ago
Simple in series circuit reference voltage is equal to source voltage.

Rajkumar said:   6 years ago
It is asking source voltage, not output voltage. So please explain this.

Parth said:   6 years ago
Vs = √Vr^2 + (Vl -Vc)^2).
= √(Vr^2 + 0). (Vl = Vc, Vl - Vc =0),
= √Vr^2,
= Vr,
= 40V.

Vaibhav ghatol said:   6 years ago
Under resonance.

Xl = xc or vl = vc and hence,
Vs = vr =40volts.
That's it.

Amol Shirgaonkar said:   6 years ago
It is √(vr^;2+(vl-vc)^2).

K.Gopalakrishna said:   6 years ago
In series circuit, the voltage differ.
125 - 125 - 40= negative.

Gnanesh said:   7 years ago
Both inductive & capacitive reactance are cancelled as both are equal.

Murali said:   7 years ago
I can't understand, so can anyone help me to get it.

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