Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 1)
1.
When these numbers are multiplied, (6 × 103) (5 × 105), the result is
Discussion:
52 comments Page 6 of 6.
Ashik said:
2 decades ago
(a^m)*(a^n)=a^(m+n)
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]
Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8
[p*(a^m)]*[q*(a^n)]=(p*q)*[a^(m+n)]
Therefore (6 x 10^3)*(5 x 10^5)=(6*5)*10^(3+5)
=30*10^8
Mahalakshmi said:
2 decades ago
Powers are added during multiplication so 6*5=30.
10^3+5=10^8 therefore 30*10^8.
10^3+5=10^8 therefore 30*10^8.
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