# Electrical Engineering - Quantities and Units - Discussion

Discussion Forum : Quantities and Units - General Questions (Q.No. 3)

3.

The number 65,000 expressed in scientific notation as a number between 1 and 10 times a power of ten is

Discussion:

30 comments Page 1 of 3.
Sai said:
3 years ago

@Jannat.

The +1is added because of 65000 = 65 * (10^3) = 6.5 * 10^4.

6.5 = (65/10).

The +1is added because of 65000 = 65 * (10^3) = 6.5 * 10^4.

6.5 = (65/10).

(3)

Er.rajwinder singh said:
3 years ago

Its simple look all given options and proper read question we already found the number between 1 to 10. look A option 0.65, c option 65 and last D 650 each are lie between 1 to 10 so answer is clear 6.6 x 10>4

(3)

P.JAGATHEESWARAN said:
4 years ago

I need perfect explanation for this question if you know please explain to me.

(1)

Avijit Hazra said:
5 years ago

I can't understand. Please explain the solutions.

(2)

Vishnu priya said:
5 years ago

I can't understand clearly. Please explain to me.

(1)

IFEANYI SOLOMON said:
5 years ago

According to me, it should be 65*10^3.

Muzaffar Baba said:
5 years ago

Sol:

65000= 65*1000

= [65*10^3]

= [65/10 * 10 * 10^3] {Multiple & divide 65 by 10}.

= [65/10 * 10 * 10^3 {10^3 3 is raised power 10},

= [65/10 * 10^4] {bases are same powers are added i.e 10^1 * 10^3=10^4},

= [6.5*10^4] {65/10=6.5}.

So, the Answer is (B).

65000= 65*1000

= [65*10^3]

= [65/10 * 10 * 10^3] {Multiple & divide 65 by 10}.

= [65/10 * 10 * 10^3 {10^3 3 is raised power 10},

= [65/10 * 10^4] {bases are same powers are added i.e 10^1 * 10^3=10^4},

= [6.5*10^4] {65/10=6.5}.

So, the Answer is (B).

(3)

Chandru said:
6 years ago

Thank you all for the given explanation.

(1)

Saritha said:
6 years ago

65,000.

65 * 1000 = 65*10^3.

65 * (10/10) * 10^3.

(65/10) * (10^1*10^3).

6.5 * 10^4.

{a^m*a^n=a^(m+n)}.

65 * 1000 = 65*10^3.

65 * (10/10) * 10^3.

(65/10) * (10^1*10^3).

6.5 * 10^4.

{a^m*a^n=a^(m+n)}.

(2)

Shivaraj said:
6 years ago

I understand now, Thank you all for explaining the problem.

(1)

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