Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 5)
5.
Approximately how many milliamperes of current flow through a circuit with a 40 V source and 6.8 k
of resistance?
of resistance?Discussion:
29 comments Page 3 of 3.
S.HARI said:
1 decade ago
I = V/R.
I = 40/6800.
= 5.88mA.
I = 40/6800.
= 5.88mA.
Tarikul Islam said:
9 years ago
Thanks to all your explanation.
Abhishek said:
7 years ago
Nice explanations, Thanks all.
Johnlerr Espenoza said:
2 years ago
I = V÷R.
I = 40÷6.8,
= 5.9Amp.
I = 40÷6.8,
= 5.9Amp.
PRIYA said:
1 decade ago
V=IR
I=V/R
V=40
R=6.8
I=5.9mA
I=V/R
V=40
R=6.8
I=5.9mA
Sanjay said:
1 decade ago
5.88 = 5.9. It is correct.
Jayesh punekar said:
1 decade ago
I=V/R
I=40/6.8
I=5.88 mA
I=40/6.8
I=5.88 mA
Anand said:
1 decade ago
Nice answer Raut mahesh
PROJIT said:
1 decade ago
I=V/R
=40/6.8
=5.88
=40/6.8
=5.88
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