Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 5)
5.
Approximately how many milliamperes of current flow through a circuit with a 40 V source and 6.8 k
of resistance?
of resistance?Discussion:
29 comments Page 1 of 3.
Johnlerr Espenoza said:
2 years ago
I = V÷R.
I = 40÷6.8,
= 5.9Amp.
I = 40÷6.8,
= 5.9Amp.
Mohibullah Shah said:
3 years ago
I = ?
V = 40V
R = 6.8 K Ohm
R = 6800 Ohm.
Since
I = V/R
I = 40/6800,
I = 0.00588,
I = 0.00588 (10^3)(10^-3)
I = 5.9 mA.
V = 40V
R = 6.8 K Ohm
R = 6800 Ohm.
Since
I = V/R
I = 40/6800,
I = 0.00588,
I = 0.00588 (10^3)(10^-3)
I = 5.9 mA.
(4)
Gavin said:
6 years ago
1A = 1000 mA.
The result of the Ohm's Law is in A (ampere).
So 5.88 A = 5880 mA.
Am I doing wrong?
The result of the Ohm's Law is in A (ampere).
So 5.88 A = 5880 mA.
Am I doing wrong?
(3)
Manish khandekar said:
6 years ago
Convert 40V to KV and calculate the current.
I = V/R. =40 * 10^3/6.8 *10^3= 5.88.
So, approximately 5.9 is the correct answer.
I = V/R. =40 * 10^3/6.8 *10^3= 5.88.
So, approximately 5.9 is the correct answer.
Abhishek said:
7 years ago
Nice explanations, Thanks all.
SHAKTI SOURAV said:
8 years ago
V=IR, SO I = V/R.
THEN I = 40/6.8, I = 5.88-> Answer.
THEN I = 40/6.8, I = 5.88-> Answer.
(4)
Tarikul Islam said:
9 years ago
Thanks to all your explanation.
Imrosekhan said:
9 years ago
As we know ohms law v = ir.
We have to calculate i so i = v/r.
Substitute those values in the above formulae.
40v/6.8 * powerten(-3) = 5.88 it is near to 5.9.
We have to calculate i so i = v/r.
Substitute those values in the above formulae.
40v/6.8 * powerten(-3) = 5.88 it is near to 5.9.
Rakesh solanki said:
9 years ago
I = V/R = 40 V/6.8 ohms = 5.88, or 5.9.
Basavaraj olekar said:
9 years ago
Because ohms law I = v/r, 40/6.8.
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