# Electrical Engineering - Ohm's Law - Discussion

### Discussion :: Ohm's Law - General Questions (Q.No.5)

5.

Approximately how many milliamperes of current flow through a circuit with a 40 V source and 6.8 k of resistance?

 [A]. 27.2 mA [B]. 59 mA [C]. 5.9 mA [D]. 590 mA

Explanation:

No answer description available for this question.

 Projit said: (Jan 20, 2011) I=V/R =40/6.8 =5.88

 Valli said: (Feb 12, 2011) The resistance value is only represent as in ohm. Then how the representation here will be ohm in the calculation?

 Vinay said: (Feb 23, 2011) To solve this question, we must covert the kilo ohm resistance in ohm resistance & then solve it whatever is the answer convert it into the milliampere.

 Raut Mahesh said: (Jun 28, 2011) I=V/R I=40/(6.8*10^3) I=5.88*10^-3 A OR I=5.88 mA

 Anand said: (Jul 22, 2011) Nice answer Raut mahesh

 Jayesh Punekar said: (Jul 24, 2011) I=V/R I=40/6.8 I=5.88 mA

 Priya said: (Jun 1, 2012) V=IR I=V/R V=40 R=6.8 I=5.9mA

 Sunny said: (Aug 27, 2012) v=40v r=6.8kv=6.8*10^3=6800 i=40/6800=0.059A=5.9A

 Prabhat said: (Oct 12, 2012) V=40v. R=6.8kv=6.8*1000=6800 ohm. I=40/6800=0.00588A. So 0.00588A=0.00588*1000=5.88 or 5.9mA.

 Pooja said: (Jul 19, 2013) Given that, V = 40v, R = 6.8Kohm, I = V/R. I = 40/6.8*(10^-3). I = 5.882mA. That is right answer.

 Pramod Shinva said: (Aug 4, 2013) Before convert the kohm TO ohms. Due to over formula is suitable for ohms. I = V/R. (1 KOhm = 1000 Ohm. So 6.8kohm = 6800 ohms). I = 40/6800. = 0.00588 Amp (1 Amps = 1000MA). = 0.00588*1000. = 5.8. = So answer is near 5.9mA. Thats way answer is 5.9mA.

 Gabriel said: (Sep 9, 2013) We know V=IR. I = V/R in this case, R = 6.8*10^3. Instead of wasting precious time. I = 40/6.8= 5.88. Appx = 5.9 and its in the option so.

 S.Hari said: (May 2, 2014) I = V/R. I = 40/6800. = 5.88mA.

 Jefrey said: (Aug 12, 2014) Given: I= V/R. I=? V= 40V. R= 6.8 kilo ohms. Solution: By using ohms law. I= V/R. I= 40/6.8. I= 5.88mA or 5.9mA.

 Venkat said: (Sep 11, 2014) V = 40v. R = 6.8 Kohms. I = 40/6.8. = 5.88mA.

 Koushal Kumar Bairwa said: (Oct 2, 2014) Given that: R = 6.8Kilo ohms = 6.8*1000 = 6800. And V=40 volt. And the ohms low is said (v) = IR. THAN I=V/R ..........1. PUTS THE VALUE OF R AND V IN EQUATION 1. I = 40/6800 = 5.88*0.001 : 0.001 = MILL(m). = 5.88mA.

 Sanjay said: (Feb 11, 2015) 5.88 = 5.9. It is correct.

 Olisemeke Job Vitalis said: (Jun 21, 2016) I = v/R => 40/6800 => 0.00588235 x 1000 => 5.88 I = 5.9

 Mikemike said: (Aug 9, 2016) I = V/R = 40V/6.8k ohms = 5.88, or 5.9.

 Basavaraj Olekar said: (Oct 22, 2016) Because ohms law I = v/r, 40/6.8.

 Rakesh Solanki said: (Nov 3, 2016) I = V/R = 40 V/6.8 ohms = 5.88, or 5.9.

 Imrosekhan said: (Nov 16, 2016) As we know ohms law v = ir. We have to calculate i so i = v/r. Substitute those values in the above formulae. 40v/6.8 * powerten(-3) = 5.88 it is near to 5.9.

 Tarikul Islam said: (Feb 9, 2017) Thanks to all your explanation.

 Shakti Sourav said: (Jun 2, 2017) V=IR, SO I = V/R. THEN I = 40/6.8, I = 5.88-> Answer.

 Abhishek said: (Jul 31, 2018) Nice explanations, Thanks all.

 Manish Khandekar said: (Jun 21, 2019) Convert 40V to KV and calculate the current. I = V/R. =40 * 10^3/6.8 *10^3= 5.88. So, approximately 5.9 is the correct answer.