Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 5)
5.
Approximately how many milliamperes of current flow through a circuit with a 40 V source and 6.8 k
of resistance?
of resistance?Discussion:
29 comments Page 2 of 3.
Gavin said:
6 years ago
1A = 1000 mA.
The result of the Ohm's Law is in A (ampere).
So 5.88 A = 5880 mA.
Am I doing wrong?
The result of the Ohm's Law is in A (ampere).
So 5.88 A = 5880 mA.
Am I doing wrong?
(3)
Prabhat said:
1 decade ago
V=40v.
R=6.8kv=6.8*1000=6800 ohm.
I=40/6800=0.00588A.
So 0.00588A=0.00588*1000=5.88 or 5.9mA.
R=6.8kv=6.8*1000=6800 ohm.
I=40/6800=0.00588A.
So 0.00588A=0.00588*1000=5.88 or 5.9mA.
Olisemeke Job Vitalis said:
9 years ago
I = v/R
=> 40/6800
=> 0.00588235 x 1000
=> 5.88
I = 5.9
=> 40/6800
=> 0.00588235 x 1000
=> 5.88
I = 5.9
SHAKTI SOURAV said:
8 years ago
V=IR, SO I = V/R.
THEN I = 40/6.8, I = 5.88-> Answer.
THEN I = 40/6.8, I = 5.88-> Answer.
(4)
Raut Mahesh said:
1 decade ago
I=V/R
I=40/(6.8*10^3)
I=5.88*10^-3 A
OR
I=5.88 mA
I=40/(6.8*10^3)
I=5.88*10^-3 A
OR
I=5.88 mA
Sunny said:
1 decade ago
v=40v
r=6.8kv=6.8*10^3=6800
i=40/6800=0.059A=5.9A
r=6.8kv=6.8*10^3=6800
i=40/6800=0.059A=5.9A
Venkat said:
1 decade ago
V = 40v.
R = 6.8 Kohms.
I = 40/6.8.
= 5.88mA.
R = 6.8 Kohms.
I = 40/6.8.
= 5.88mA.
Mikemike said:
9 years ago
I = V/R = 40V/6.8k ohms = 5.88, or 5.9.
Rakesh solanki said:
9 years ago
I = V/R = 40 V/6.8 ohms = 5.88, or 5.9.
Basavaraj olekar said:
9 years ago
Because ohms law I = v/r, 40/6.8.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers