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Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 2)
Ohm's Law
2.
If 750 µA is flowing through 11 k of resistance, what is the voltage drop across the resistor?
8.25 V
82.5 V
14.6 V
146 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
60 comments Page 3 of 6.
Richa said:   1 decade ago
1 Micro amp = 10^-6 Amp.
1 Kilo Ohm = 10^3 ohm.
V = IR.
V = (11*10^3)*(750*10^-6).
= 8.25.
Aasai thambi said:   6 years ago
i=750 microamps =>0.000750 amps.
r=11000ohms,
0.000750*11000 =>0.750 * 11=>8.25v.
PAMMI said:   1 decade ago
V = IR.
V = 0.00075*11000.
V = 8.25.

Because,
1 MICRO AMP = 1000000.
1 KILLO OHMS = 1000.
Nagaraja m said:   1 decade ago
V = ?
i = 750 UA, = 0.750 A.
R = 11 K ohms = 1100.

WKT, V = iR.

So, = 0.750*1100 = 8.25.
Manthar ali said:   1 decade ago
V = IR.
V = 750*10^-6*11*10^3.
V = 750*10^-3*11=8250.

So V = 8250*10^-3.
V = 8.250 V.
Rahul chouhan said:   10 years ago
Ohms.

V = IR.

I = 750 UA.

R = 11 kilo ohm.

V = 750*11.

V = 8250/1000.

V = 8.25.
Kalpesh said:   1 decade ago
Mr. M. Neduchezhian is right & nice explanation.

Thanks for given right answer.
Haroon Zaman said:   5 years ago
V = IR.
V = (750*10^-6)(11*10^3),
V = 8250*10^-3,
V = 8.25*10^3*10^-3,
V = 8.25.
(4)
Deepak mp said:   1 decade ago
V = IR.
V = 750*11 = 8250.
V = 8250.

V/1000.
8250/1000 = 8.25.

Ans = 8.25V.
Jagpreet said:   1 decade ago
8.25 is actual supply votage and its not the drop across 11 kohm resistor.
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