Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 2)
2.
If 750 µA is flowing through 11 k
of resistance, what is the voltage drop across the resistor?
of resistance, what is the voltage drop across the resistor?Discussion:
60 comments Page 2 of 6.
Srinivas said:
1 decade ago
@jag
Actual voltage supply is the supply voltage giving by the source, voltage drop is the fall in the voltage because of resistance of the resistor in circuit.
Actual voltage supply is the supply voltage giving by the source, voltage drop is the fall in the voltage because of resistance of the resistor in circuit.
Jayesh J. Joshi said:
9 years ago
I = 750 micro amp.
= 0.00075 amp.
= 75/1000000 amp.
R = 11 kilo ohm.
= 11 * 1000 ohm.
= 110000 ohm.
V = IR.
= 75/1000000 * 110000.
= 8.25 VOLT => ANS.
= 0.00075 amp.
= 75/1000000 amp.
R = 11 kilo ohm.
= 11 * 1000 ohm.
= 110000 ohm.
V = IR.
= 75/1000000 * 110000.
= 8.25 VOLT => ANS.
Amar bhuan 'binka' said:
1 decade ago
I = 750 micro amp.
= 0.00075 amp.
= 75/1000000 amp.
R = 11 kilo ohm.
= 11*1000 ohm.
= 110000 ohm.
V = IR.
= 75/1000000*110000.
= 8.25 VOLT ANS.
= 0.00075 amp.
= 75/1000000 amp.
R = 11 kilo ohm.
= 11*1000 ohm.
= 110000 ohm.
V = IR.
= 75/1000000*110000.
= 8.25 VOLT ANS.
Imrosekhan said:
9 years ago
Here, v = ir.
Small idea is micro is powerten(-6) & kilo is powerten(--3).
750 * powerten(-6) =0.00075,
v = 0.00075 * 110000 = 8.25.
Small idea is micro is powerten(-6) & kilo is powerten(--3).
750 * powerten(-6) =0.00075,
v = 0.00075 * 110000 = 8.25.
Joy jumbo itah said:
1 decade ago
Given that;
I=750microamps ie;750/1000 =0.750A
R=11kil0 ohms
therefore V = I*R from ohm's law
V = 0.75*11=8.25v
It's right
I=750microamps ie;750/1000 =0.750A
R=11kil0 ohms
therefore V = I*R from ohm's law
V = 0.75*11=8.25v
It's right
Srivani said:
1 decade ago
Current(I)=750X10^-6 A,
R=11X10^3 ,
V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3).
V=750X11X10^-3.
V=0.75X11=8.25 V.
R=11X10^3 ,
V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3).
V=750X11X10^-3.
V=0.75X11=8.25 V.
Chisom rapheal mark said:
8 years ago
V = IR.
I = 750uA = 750/1000000 = 0.00075A,
R = 11kohms = 11 * 1000 = 11000ohms,
.'.V = 0.00075*11000,
V = 8.25v.
I = 750uA = 750/1000000 = 0.00075A,
R = 11kohms = 11 * 1000 = 11000ohms,
.'.V = 0.00075*11000,
V = 8.25v.
Rahul Singh Rathore said:
5 years ago
I=750mic.amp =.750mili amp =.000750 amp.
R= 11 k ohms = 11000 ohm,
V= IR=. 000750 * 11000 =.750 * 11 = 8.25V.
R= 11 k ohms = 11000 ohm,
V= IR=. 000750 * 11000 =.750 * 11 = 8.25V.
(9)
Anand said:
1 decade ago
I=750X10^-6 A,
R=11X10^3 ,
V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3)
V=750X11X10^-3
V=0.75X11=8.25 V
R=11X10^3 ,
V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3)
V=750X11X10^-3
V=0.75X11=8.25 V
Nju said:
1 decade ago
According to my concept too 11kilo ohms must be 11000ohms.
So do I disagree with the ans i.e 8. 25v.
So do I disagree with the ans i.e 8. 25v.
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