Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 2)
2.
If 750 µA is flowing through 11 k of resistance, what is the voltage drop across the resistor?
8.25 V
82.5 V
14.6 V
146 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
60 comments Page 6 of 6.

Benard Istifanus said:   6 years ago
Thanks all for explaining it.

Vishal said:   5 years ago
Good Explanation, thanks all.

Krunal Shah said:   1 decade ago
Thank u 4 giving explanation

Suresh babu said:   1 decade ago
V=IR

V=(0.750)*(11)

V=8.25
(1)

Faisal said:   7 years ago
8.25 is the correct answer.

Braj Kumar said:   8 years ago
Right answer is 8.25 volt.

Kranthi bk said:   2 years ago
Thanks all for explaining.
(10)

Nans said:   8 years ago
Thanks @Nedunchezhian.

Punithajothi said:   1 decade ago
v=i*r its simple

Anil said:   1 decade ago
v=i*r


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