Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 2)
2.
If 750 µA is flowing through 11 k
of resistance, what is the voltage drop across the resistor?

Discussion:
60 comments Page 6 of 6.
Benard Istifanus said:
6 years ago
Thanks all for explaining it.
Vishal said:
5 years ago
Good Explanation, thanks all.
Krunal Shah said:
1 decade ago
Thank u 4 giving explanation
Suresh babu said:
1 decade ago
V=IR
V=(0.750)*(11)
V=8.25
V=(0.750)*(11)
V=8.25
(1)
Faisal said:
7 years ago
8.25 is the correct answer.
Braj Kumar said:
8 years ago
Right answer is 8.25 volt.
Kranthi bk said:
2 years ago
Thanks all for explaining.
(10)
Nans said:
8 years ago
Thanks @Nedunchezhian.
Punithajothi said:
1 decade ago
v=i*r its simple
Anil said:
1 decade ago
v=i*r
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