# Electrical Engineering - Ohm's Law - Discussion

### Discussion :: Ohm's Law - General Questions (Q.No.2)

2.

If 750 µA is flowing through 11 k of resistance, what is the voltage drop across the resistor?

 [A]. 8.25 V [B]. 82.5 V [C]. 14.6 V [D]. 146 V

Explanation:

No answer description available for this question.

 Suresh Babu said: (Dec 15, 2010) V=IR V=(0.750)*(11) V=8.25

 Anil said: (Jan 25, 2011) v=i*r

 Punithajothi said: (Feb 21, 2011) v=i*r its simple

 Sareeran said: (Mar 19, 2011) I=750microamps=0.75A R=11kilo ohms V=I*R Therefore V=0.75*11 V=8.25

 Vshree said: (Mar 29, 2011) According to Ohm's Law: V = I x R

 Joy Jumbo Itah said: (Apr 14, 2011) Given that; I=750microamps ie;750/1000 =0.750A R=11kil0 ohms therefore V = I*R from ohm's law V = 0.75*11=8.25v It's right

 4Getfull said: (Apr 16, 2011) Regarding the ohms wouldn't k represent 1,000, if not what is the abbreviation represent? or did i just get it it by realizing the microamps has already been converted by devising by 1,000 and thats why 11 works instead of 11,000

 Nju said: (May 14, 2011) According to my concept too 11kilo ohms must be 11000ohms. So do I disagree with the ans i.e 8. 25v.

 M.Nedunchezhian said: (May 16, 2011) Ya I have same doubt like @4getfull.

 M.Nedunchezhian said: (May 16, 2011) All above methods are wrong. 1 microamphere = 10^-6 Amphere. Therefore, 750 microamphere = 750/1000000=0.00075 Amphere. 11 kiloohm = 11000 ohms. V=I*R V=0.00075*11000=8.25V.

 Krunal Shah said: (Jul 3, 2011) Thank u 4 giving explanation

 Gobimohanraj said: (Jul 11, 2011) Nice and Correct Explanation Mr.M.Neduchezhian

 Prabu said: (Jul 14, 2011) Mr.M.Neduchezhian vry crt & nice explanation.

 Anand said: (Jul 22, 2011) I=750X10^-6 A, R=11X10^3 , V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3) V=750X11X10^-3 V=0.75X11=8.25 V

 Kalpesh said: (Nov 17, 2011) Mr. M. Neduchezhian is right & nice explanation. Thanks for given right answer.

 Jagpreet said: (Nov 23, 2011) 8.25 is actual supply votage and its not the drop across 11 kohm resistor.

 Naveen said: (Jan 22, 2012) Dear Friends,, Its very easy to find the answer in Exams...as the thing is Resistor never consumes the type of current..it always gives out what ever it have. So no use of calulating in this way... Just it is produsing 11 and I is 75*10^-6 ie .75*11=8025

 Cyko said: (Feb 7, 2012) @ M. Nedunchezhian very good explained thank you.

 Jagdish Raval said: (Feb 15, 2012) What is the Difference between actual Voltage supply & Voltage Drop?

 Srinivas said: (Mar 18, 2012) @jag Actual voltage supply is the supply voltage giving by the source, voltage drop is the fall in the voltage because of resistance of the resistor in circuit.

 Khan said: (Apr 21, 2012) What is the difference between actual supply & voltage drop.

 Samir said: (May 10, 2012) Simple V = IR. 0.75*11 = 8.25.

 Srivani said: (Dec 7, 2012) Current(I)=750X10^-6 A, R=11X10^3 , V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3). V=750X11X10^-3. V=0.75X11=8.25 V.

 Deepak Mp said: (Jan 6, 2014) V = IR. V = 750*11 = 8250. V = 8250. V/1000. 8250/1000 = 8.25. Ans = 8.25V.

 M.Arasumani said: (Jan 27, 2014) V = IR. V = ? I = 750x10^-6(micro amp to amp). R = 11000(kilo ohms to ohms). First all the unit come same unit ohms, amp, volt that's way answer correct other wise wrong. V = 8.25.

 Tushar K Naskar said: (Apr 7, 2014) V = IR. V = 750*11. V = 8250. V = 8250/1000. V = 8.250 V.

 Suman Lal Bharti said: (Jul 15, 2014) Given that, Current, I= 750 Micro-Ampere= 750/1000000 Amp.= .00075 Amp. Resistance, R= 11 Kilo-Ohms= 11*1000 Ohms= 11000 Ohms. Now by using Ohm's Law, V=I*R; Hence, V= .00075*11000= 8.25 Volts.

 Richa said: (Sep 12, 2014) 1 Micro amp = 10^-6 Amp. 1 Kilo Ohm = 10^3 ohm. V = IR. V = (11*10^3)*(750*10^-6). = 8.25.

 Amar Bhuan 'Binka' said: (Nov 13, 2014) I = 750 micro amp. = 0.00075 amp. = 75/1000000 amp. R = 11 kilo ohm. = 11*1000 ohm. = 110000 ohm. V = IR. = 75/1000000*110000. = 8.25 VOLT ANS.

 Bharat said: (Nov 21, 2014) V = IR. V = 0.000750X11000. V = 8.25 V.

 Manthar Ali said: (Mar 27, 2015) V = IR. V = 750*10^-6*11*10^3. V = 750*10^-3*11=8250. So V = 8250*10^-3. V = 8.250 V.

 Nagaraja M said: (Jun 26, 2015) V = ? i = 750 UA, = 0.750 A. R = 11 K ohms = 1100. WKT, V = iR. So, = 0.750*1100 = 8.25.

 Pammi said: (Jul 15, 2015) V = IR. V = 0.00075*11000. V = 8.25. Because, 1 MICRO AMP = 1000000. 1 KILLO OHMS = 1000.

 Waiswa Mathius said: (Aug 25, 2015) From ohm's law, V=IR where are is the resistance of the material in Ohms, V is the voltage supplied to the appliance in volts and I the current flowing in Amperes. V=IR. 1 micro amperes = 0.000001 A. 750 micro amperes = 750*0.000001. = 0.00075 A. 1 kilo ohm = 1000 ohms. 11 kilo ohm = 11*1000. = 11000 ohms. Therefor, V = 0.00075*11000 = 8. 5 V.

 Rahul Chouhan said: (Sep 13, 2015) Ohms. V = IR. I = 750 UA. R = 11 kilo ohm. V = 750*11. V = 8250/1000. V = 8.25.

 Jayesh J. Joshi said: (Jun 16, 2016) I = 750 micro amp. = 0.00075 amp. = 75/1000000 amp. R = 11 kilo ohm. = 11 * 1000 ohm. = 110000 ohm. V = IR. = 75/1000000 * 110000. = 8.25 VOLT => ANS.

 Imrosekhan said: (Nov 16, 2016) Here, v = ir. Small idea is micro is powerten(-6) & kilo is powerten(--3). 750 * powerten(-6) =0.00075, v = 0.00075 * 110000 = 8.25.

 Chisom Rapheal Mark said: (Mar 1, 2017) V = IR. I = 750uA = 750/1000000 = 0.00075A, R = 11kohms = 11 * 1000 = 11000ohms, .'.V = 0.00075*11000, V = 8.25v.

 Nans said: (Mar 17, 2017) Thanks @Nedunchezhian.

 Abhinandan Asd said: (May 10, 2017) Thanks for your solution @Nedunchezhian.

 Jana333 said: (Jun 23, 2017) How to calculate micro amps to amps? 1A=10^3 mA 1A=10^6 V=IR, I=( 750/10^6), =0.00075A THEN, 11K OHM= (11*1000), = 11000 OHMS, V=(11000*0.00075) =8.25V Ans. I think everyone understands this

 Indranil Das said: (Aug 20, 2017) voltage drop refers to the voltage consumed by the particular resistance, Here it is 8.25v and supply voltage whatever may be (here it is not mentioned) should be greater than 8.25v.

 Braj Kumar said: (Nov 3, 2017) Right answer is 8.25 volt.

 Madhuri Gulhane said: (Dec 26, 2017) V = IR. V = 750*10^-6*11*10^3. V = 8.25V.

 Faisal said: (Apr 4, 2018) 8.25 is the correct answer.

 Kadija said: (Jun 19, 2018) Micro amp is different from milli amp. I = in Amp. Amp -> millli Amp -> micro Amp, 1 --> 1000 --> 1000000. So, I thought we should divide 750 microamps into 1000000 to get the unit Amp. Please clarify.

 Sanjeeb Kumar Behera said: (Jul 25, 2018) V = IR V = (0.750)*(11) V = 8.25. (A).

 Meghray said: (Nov 22, 2018) Ans is [B] 82.5. Given data: I = 750microAmps = 750 * 10^-6 amps. Resistance(R)= 11kohm= 11*10^3ohm Voltage drop (Vd)= I*R. = (750 *10^-6 )*(11*10^3), = 82.5V.

 Aasai Thambi said: (Jul 21, 2019) i=750 microamps =>0.000750 amps. r=11000ohms, 0.000750*11000 =>0.750 * 11=>8.25v.

 Benard Istifanus said: (Sep 27, 2019) Thanks all for explaining it.