Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 4)
4.
A resistor is connected across a 50 V source. What is the current in the resistor if the color code is red, orange, orange, silver?
Discussion:
79 comments Page 5 of 8.
Barnali said:
1 decade ago
Color bands for 1.5 Ohm resistor will be?
Abhishek John said:
10 years ago
First Band Red = 2.
Second Band Orange = 3.
(Repeat) Multiplier Band Orange = 10*^3 or 1000.
Silver = +/-10%.
Total = 23000*(+/-10%).
I = V/R.
I = 50/23000A.
I = 0.00217A.
I = 2.17mA - Answer.
Or 2.2mA.
Second Band Orange = 3.
(Repeat) Multiplier Band Orange = 10*^3 or 1000.
Silver = +/-10%.
Total = 23000*(+/-10%).
I = V/R.
I = 50/23000A.
I = 0.00217A.
I = 2.17mA - Answer.
Or 2.2mA.
Shruthi said:
10 years ago
V=50 V, I=?
R = red, orange, orange, silver i.e. 23x10^3 = 23 k.
I = V/R.
= 50/23000.
= 2.17 mA.
R = red, orange, orange, silver i.e. 23x10^3 = 23 k.
I = V/R.
= 50/23000.
= 2.17 mA.
Goutham said:
10 years ago
Thank you very much guys for making me to understand.
Rakesh said:
10 years ago
Without calculator, how it's calculated?
AKRITI said:
9 years ago
CLEAR VALUE OF GOLD IS 5% OR 20%.
Awais said:
9 years ago
It is 5% of Gold and 20% of None.
Maneesh Mahajan said:
9 years ago
Very nice explanation. I am satisfied. Thank you all.
JAVARIA said:
9 years ago
Marvelous explanation. I am really much satisfied from this explanation. Thank you to all.
Mahesh kumar k said:
9 years ago
Good explanation. Thanking you all.
I want to know easy method to remember the colour coding. Can anyone help me?
I want to know easy method to remember the colour coding. Can anyone help me?
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