Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 4)
4.
A resistor is connected across a 50 V source. What is the current in the resistor if the color code is red, orange, orange, silver?
2 mA
2.2 mA
214 mA
21.4 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
78 comments Page 1 of 8.

K.Rekha said:   1 decade ago
The current in the resistor if the color code is red, orange, orange, silver why?

Priyaaru said:   1 decade ago
resistance = 23* (10)^3 (+ or -)10 = 23010 or 22990
current = ( voltage / resistance)= (50 / 23010)= 2.2 mA

Tushar singhal said:   1 decade ago
I'm not satisfy with priyaaru ans. because 23*(10)^3(+or-)10% means 23000(+or-)10% means 23000(+or-)2300.

Alok kumar said:   1 decade ago
Can anybody understand me about colour code?! please.

Sathish said:   1 decade ago
Colour code is like BBROYGBVGW

We used say as: BB Roy Great Britain Very Good Wife

Black 0 1 1
Brown 1 1 1 10
Red 2 2 2 100
Orange 3 3 3 1,000
Yellow 4 4 4 10,000
Green 5 5 5 100,000
Blue 6 6 6 1,000,000
Violet 7 7 10,000,000
Gray 8 8 100,000,000
White 9 9 1,000,000,000
None 20%
Silver 10%
Gold 5%

SO RED is 2 orange 3 and third orange 10 to the power of that vlaue so 10000

so R=23000
I=V/R
=50/23000
=2.2mA

Vinay said:   1 decade ago
That is very good explanation

Joy jumbo itah said:   1 decade ago
I understand better now.

Isocuraphil said:   1 decade ago
Please help me on how to memorize color code values and multiplier. Thanx.

Aniruddha said:   1 decade ago
Thanks Suresh & Satish for make me clear about colour coding. But second orange code is nt clear easyly. Please clear my dout.

Thenmozhi said:   1 decade ago
THANKS...... Now i'm very clear with the colour codes....


Post your comments here:

Your comments will be displayed after verification.