Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 4)
4.
A resistor is connected across a 50 V source. What is the current in the resistor if the color code is red, orange, orange, silver?
2 mA
2.2 mA
214 mA
21.4 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
79 comments Page 3 of 8.

Rakesh said:   10 years ago
Without calculator, how it's calculated?

Goutham said:   10 years ago
Thank you very much guys for making me to understand.

Nandipha said:   8 years ago
What is the resistor of Orange, violet, yellow, gold, brown?

Abhishek John said:   10 years ago
First Band Red = 2.

Second Band Orange = 3.

(Repeat) Multiplier Band Orange = 10*^3 or 1000.

Silver = +/-10%.

Total = 23000*(+/-10%).

I = V/R.

I = 50/23000A.
I = 0.00217A.
I = 2.17mA - Answer.

Or 2.2mA.

Barnali said:   1 decade ago
Color bands for 1.5 Ohm resistor will be?

Shujaa said:   9 years ago
Thanks for all the explanation, now I understand this problem.

Imrosekhan said:   9 years ago
Colour code is like BBROYGBVGW.

We used say as: BB Roy Great Britain Very Good Wife

Black---> 0 1 1
Brown---> 1 1 1 10
Red ---> 2 2 2 100
Orange -->3 3 3 1,000
Yellow---> 4 4 4 10,000
Green---> 5 5 5 100,000
Blue ---> 6 6 6 1,000,000
Violet---> 7 7 10,000,000
Gray ---> 8 8 100,000,000
White --->9 9 1,000,000,000
None--->20%
Silver--->10%
Gold--->5%

SO RED is 2 orange 3 and third orange 10 to the power of that value so 10000.

So R = 23000.
as we know that v = IR.
I = V/R.
= 50/23000,
= 2.2mA.

Saurabh said:   9 years ago
Very well explained, thanks @Sathish.

Rahul said:   9 years ago
Which is the correct value of gold 20% or 5%?

Please clear it.

SHANTU said:   1 decade ago
All color code understand thanks for all of you.


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