Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 4)
4.
A resistor is connected across a 50 V source. What is the current in the resistor if the color code is red, orange, orange, silver?
2 mA
2.2 mA
214 mA
21.4 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
78 comments Page 2 of 8.

Prakash pritam said:   9 years ago
I think in this question we are assuming the minimum value of resistance, Hence the value of resistance is 23 * 10^3 - 10% = 22.7 * 10^3,
Now, V/R = I,
=> 50/22.7 * 10^3 = 2.20 mA.

SKS said:   9 years ago
If resistor will contain 5 color bands then how can we able to determine it's value?

Jayesh J. Joshi said:   9 years ago
Keep this as "BBROY went to Great Britain to get Very Good Wife with Gold and Silver".

Resistor values can be known by the colour band.
0 black
1 blue
2 red
3 orange
4 yellow
5 green
6 blue
7 violet
8 grey
9 white

The resistor value is given by 1st 3 bands.
Start from left most band, 3rd value is a power of 10.

Ans: red(2), orange(3), orange(10^3).
So, the value becomes 23 * 10^3.

Elsadig said:   9 years ago
Good job.

But I still have the question.

Green = 5.
Green = 8.

Which is right and why we use 2 values?

Mahesh kumar k said:   9 years ago
Good explanation. Thanking you all.

I want to know easy method to remember the colour coding. Can anyone help me?

JAVARIA said:   9 years ago
Marvelous explanation. I am really much satisfied from this explanation. Thank you to all.

Maneesh Mahajan said:   9 years ago
Very nice explanation. I am satisfied. Thank you all.

Awais said:   9 years ago
It is 5% of Gold and 20% of None.

AKRITI said:   9 years ago
CLEAR VALUE OF GOLD IS 5% OR 20%.

Rakesh said:   10 years ago
Without calculator, how it's calculated?


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