Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385 
38.5
3.1
31
Discussion:
103 comments Page 9 of 11.
Saravanakumar said:
1 decade ago
TO use the ohms law V=IR Then R=V/I
R=110/3.5=31.428
R=110/3.5=31.428
Arun said:
1 decade ago
V = IR.
R = V/I.
R = 110 / 3.5.
R = 31.42 ohm.
R = V/I.
R = 110 / 3.5.
R = 31.42 ohm.
Srinivas said:
9 years ago
V = IR.
V = 110.
I = 3.5.
R = V/I = 110/3.5 = 31.
V = 110.
I = 3.5.
R = V/I = 110/3.5 = 31.
Narayan ch sahoo said:
1 decade ago
Very nice question & very beautiful answers.
PABITR AKUMAR BEHERA said:
7 years ago
V = I * R
V = 110
I = 3.5
R = 110/3.5 = 31.428.
V = 110
I = 3.5
R = 110/3.5 = 31.428.
K.Niranjan said:
1 decade ago
According to ohms law V=IR
r=v/i=110/3.5=31.42
r=v/i=110/3.5=31.42
Paramak issahaku Biila said:
5 years ago
It is very helpful, thanks all for explaining.
(6)
AVATAR BEHERA said:
1 decade ago
R = V/I.
R = 110/3.5 = 31.428.
Appro = 31.
R = 110/3.5 = 31.428.
Appro = 31.
Mahendra said:
1 decade ago
What is the proper definition of ohm's law?
ASHISH KHAN said:
1 decade ago
YES, R=V/I
=110/3.5
= 31OHM.
=110/3.5
= 31OHM.
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