Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385 
38.5
3.1
31
Discussion:
102 comments Page 8 of 11.
Chittaranjaan said:
1 decade ago
Ya right, but if there would be another option stating 32 then..
Mukesh Kumar Ghotra bemoth said:
9 years ago
V = lR.
R = v\l.
V = 110 v.
I = 3.5 A.
R =110\3.5 = 31.4 ohm.
R = v\l.
V = 110 v.
I = 3.5 A.
R =110\3.5 = 31.4 ohm.
Swapna said:
1 decade ago
Its exactly correct. We have to remember this formula.
V=IR.
V=IR.
Bhushan said:
9 years ago
What is the answer if there will be another option as. 31.5?
M.NARENDRA said:
1 decade ago
According to ohm's law
V=IR =>R=V/I
=>R=110/3.5
R=31.4
V=IR =>R=V/I
=>R=110/3.5
R=31.4
MOHAN said:
1 decade ago
Yes according to ohms law
V = IR
R = V/I
= 110/3.5
= 31 ohm
V = IR
R = V/I
= 110/3.5
= 31 ohm
Jitendra Behera said:
1 decade ago
We know that R=V/I.
R=110/3. 5=31. 4ohm.
Ans- [D]. 31ohm.
R=110/3. 5=31. 4ohm.
Ans- [D]. 31ohm.
Oludare inioluwa said:
2 years ago
I = V/R,
I = 3.5,
V = 110,
R = V/I,
R = 110/3.5,
= 31.4.
I = 3.5,
V = 110,
R = V/I,
R = 110/3.5,
= 31.4.
(3)
JEYA SELVAM.P said:
1 decade ago
V=IR.
V=110V
I=3.5A
R=?
R=V/I
R=110/3.5
R=31.4
R=31ohm.
V=110V
I=3.5A
R=?
R=V/I
R=110/3.5
R=31.4
R=31ohm.
Saravanakumar said:
1 decade ago
TO use the ohms law V=IR Then R=V/I
R=110/3.5=31.428
R=110/3.5=31.428
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers