Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 7 of 11.

Subha S said:   1 decade ago
I = V/R.
R = V/I.
R = ?

V = 110V.
I = 3.5A.

R = 110/3.5.
R = 31.428.

JAGANNATH said:   9 years ago
According to ohm's law V = IR.
Then, I = V/R.
R = 110/3.5 = 31.4285.

Goura Krushna Patra said:   1 year ago
According to Ohm's law.
I = V/R.
So, R = V/I.
R = 110/3.5 = 31.4286Ω.
(6)

Saravanan.k said:   1 decade ago
Given
V=110V
I=3.5A

By Ohms law
V=IR
R=V/I
=110/3.5
=31.428
=31 Ohms

Sibo mondolo said:   1 decade ago
We known that, *according to ohm's law R = V/I =110/3.5 = 31.42 ohm.

Rajesh kumar pradhan said:   1 decade ago
I=V/R. R=V/I. R=? V=110V. I=3.5A. R=110/3.5. R= 31.428.

Sarath said:   9 years ago
According to Ohm's law:

V = IR,

R = V/I,

R = 110/3.5,

R = 31.42.

Shalini said:   1 decade ago
I = 3.5A.
V = 110V.

By ohm's law,
V = IR.

110 = 3.5R.
R = 31 ohm.

Aba said:   1 decade ago
Yes the 'D' is right answer i.e. R =31 ohms according to ohms law.

SATHISH said:   10 years ago
V = IR.

110 = 3.5*R.

R = 110/3.5.

R = 31.42 [CUT OFF].

R = 31.


Post your comments here:

Your comments will be displayed after verification.