Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 6 of 11.

Satish said:   1 decade ago
Its exactly correct. We have to remember this formula.
I=V/R or V=IR or R=V/I.

Sudhanshu Pal said:   1 decade ago
V = IR.
So 110 = 3.5 R.

R = V/I.
So R = 110/3.5.

So R = 31.42.
So Answer D.

Shubham Pandey said:   8 years ago
Acc. To ohm's law.
V=IR.
Or R= V/I.
Then,
R=110/3.5.
=>1100/35.
=31.42.

Amir said:   1 decade ago
I(A)=voltage/resistance
or
I=E/R
or
R=E/I
= 110/3.5
=31.42
=31

Prem said:   1 decade ago
According to ohm's law V = IR

Resistance = voltage/current
=110/3.5
=31.4

O p gautam said:   1 decade ago
Resistance may not be measured in decimal. So answer in 31 ohm is correct.

Negi said:   1 decade ago
Well 32 ohms would be right cause it's coming 31.428 so round off 32 ohm.

SHAKRU JARPULA said:   1 decade ago
We know that from ohm's law.

V = IR.

Given, R=110/31.5 = 31.428

R = 31

Sangeetha said:   1 decade ago
According to ohms law.

V=IR.
Therefore.
R=V/I.

R=110/3.5.

=31.4 ohms.

Jepoy said:   1 decade ago
Given:

V=110V.
I=3.5A.
R=?

Solution:

R= V/I.
R= 110/3.5.
R= 31 ohms.


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