Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 1 of 11.

BALA MURUGAN M said:   2 years ago
Ohm's Law firm v = IR.
Then R = V/I.

Given;
V = 110v.
I = 3.5A.
Therefore
R = 110/3.5 = 31.428.
So, the given answer is correct.
(8)

Jayaraj.R said:   5 years ago
Ohm's Law firm v = IR.
Then R=V/I

Given

V = 110v.
I = 3.5A.
Therefore R = 110/3.5 = 31.428.
So the given answer is correct.
(7)

Paramak issahaku Biila said:   4 years ago
It is very helpful, thanks all for explaining.
(6)

Goura Krushna Patra said:   1 year ago
According to Ohm's law.
I = V/R.
So, R = V/I.
R = 110/3.5 = 31.4286Ω.
(6)

Ankita said:   2 years ago
Given data
V = 110 volt.
I = 3.5 A.
We know that;
According to Ohm's law-
V = IR.
So, R = V/I
R = 110/3.5
R = 31.4 Ohm.
(5)

Oludare inioluwa said:   2 years ago
I = V/R,
I = 3.5,
V = 110,
R = V/I,
R = 110/3.5,
= 31.4.
(3)

BALA said:   2 years ago
The answer is 31.4.
(3)

Er KUNA SAHOO said:   1 year ago
As per ohms law R = V/I.
V = 110V.
I = 3.5.
R = 110/3.5 = 31.42.

ANS R = 31OHMS IS THE RIGHT ANSWER.
(2)

Er.J.Arun Ganesh said:   6 years ago
As per ohms law,

Voltage V = 110.
Current I = 3.5.
Resistance R = X.

Formula,
R = V/I.

R = 110/3.5 = 31.42 ohms.

Resistance of heating element is 31.42 ohms.
(1)

John lerr said:   2 years ago
R = V÷I.
R = 110÷3.5.
= 3.1 Ohms.
(1)


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