Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385 
38.5
3.1
31
Discussion:
102 comments Page 11 of 11.
PABITR AKUMAR BEHERA said:
7 years ago
V = I * R
V = 110
I = 3.5
R = 110/3.5 = 31.428.
V = 110
I = 3.5
R = 110/3.5 = 31.428.
Aman said:
7 years ago
According to this,
if you want to simplify the voltage then it will be, V=R * A(V=>31 * 3.5 = 108.5).
Voltage means to push, so push must have to multiply by A(amount of electron) and R(anti-push).
And if you want to simplify the R(anti-push).
Then,
R(anti-push) = V(push)/A(amount of electron),
R = V/A.
if you want to simplify the voltage then it will be, V=R * A(V=>31 * 3.5 = 108.5).
Voltage means to push, so push must have to multiply by A(amount of electron) and R(anti-push).
And if you want to simplify the R(anti-push).
Then,
R(anti-push) = V(push)/A(amount of electron),
R = V/A.
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