Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 1 of 11.

Prem said:   1 decade ago
According to ohm's law V = IR

Resistance = voltage/current
=110/3.5
=31.4

Reshma said:   1 decade ago
Ya its absolutely right.......

R.ASHOK said:   1 decade ago
According ohm's law it states that the resistance is directly propostional to the voltage & inversly propostional to the current at constant temprature.
i.e R=V/I
R= 110/3.5
R=31.4285ohm so here we are taking approximative value 31.

Amir said:   1 decade ago
I(A)=voltage/resistance
or
I=E/R
or
R=E/I
= 110/3.5
=31.42
=31

Chittaranjaan said:   1 decade ago
Ya right, but if there would be another option stating 32 then..

SWAMY.M said:   1 decade ago
Yes, I accept it is correct because according to ohm's law state that"resistance is directly propostional to the vg,and invesly propostional to current. Hence we can conclude that I=V/R

I=3.5,v=110,R=?
R=V/I,R=110/3.5=31.42 apprsmtly=31 we can put. that solve.

Hpc said:   1 decade ago
Thanks prem.

Sambathfire said:   1 decade ago
r=v/i
r=110/3.5
r=31.4
r=31

Saravanakumar said:   1 decade ago
TO use the ohms law V=IR Then R=V/I
R=110/3.5=31.428

Siva nanda said:   1 decade ago
Ohms law V=IR.

Then R=V/I.

Given,

V=110v.

I=3.5A

Therfore R=110/3.5=31.428.

So the given answer is correct.


Post your comments here:

Your comments will be displayed after verification.