Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385 
38.5
3.1
31
Discussion:
102 comments Page 10 of 11.
Magesh said:
8 years ago
Solve it by using ohm' law.
Sujin adhikari said:
8 years ago
Under a constant physical condition (i.e temperature remains constant) current flowing through the conductor is directly proportional to voltage or (potential different) applied across its end.
Pavankumar said:
8 years ago
From the given question, it is related to ohm's law V=IR.
then,
from the question, V=110V and I=3.5A.
R=V/A=110/3.5=31.42=31.
then,
from the question, V=110V and I=3.5A.
R=V/A=110/3.5=31.42=31.
Oyelowo Oluwatobiloba said:
8 years ago
From
V = IR
(where V is the Voltage (volts), I current (Ampere), and R resistance(ohms)
V=110v
I=3.5A
R=?
Making R subject from V=IR by dividing through by I
We have R=V/I
R=110/3.5
R= 31.4ohms
Approximately 31ohms.
V = IR
(where V is the Voltage (volts), I current (Ampere), and R resistance(ohms)
V=110v
I=3.5A
R=?
Making R subject from V=IR by dividing through by I
We have R=V/I
R=110/3.5
R= 31.4ohms
Approximately 31ohms.
Er.Mukesh kumar said:
8 years ago
According yo law, 31 is right.
Braj Kumar said:
8 years ago
According to ohm's low R =V/I,
V= 110V.
I = 3.5A.
Put the value of voltage and current above formula given.
R = 110/3.5.
Correct answer is 31 ohm.
V= 110V.
I = 3.5A.
Put the value of voltage and current above formula given.
R = 110/3.5.
Correct answer is 31 ohm.
Deepak prakash said:
8 years ago
According to ohms law, I is directly proportional to V.
so. V=IR
R=v/I
R=110/3.5=31.42.
so. V=IR
R=v/I
R=110/3.5=31.42.
Shubham Pandey said:
8 years ago
Acc. To ohm's law.
V=IR.
Or R= V/I.
Then,
R=110/3.5.
=>1100/35.
=31.42.
V=IR.
Or R= V/I.
Then,
R=110/3.5.
=>1100/35.
=31.42.
Bibek said:
7 years ago
The correct answer is 31.4 Ω.
T ASHOK said:
7 years ago
Resistance =voltage /current.
So, R =110/3.5,
So, R =110/35/10,
So, R =110/35 *10,
R=31.4 Ω.
So, R =110/3.5,
So, R =110/35/10,
So, R =110/35 *10,
R=31.4 Ω.
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