Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 9 of 11.

Onyia said:   9 years ago
By using for OHMS law.

Given:

R = V/I.

So, R = 110/3.5 = 31.42.

Answer: 31 OHM.

Balasubramaniyan.N said:   9 years ago
Ohm law V = IR.

V = 110V, I=3.5A, R=?,
R = V/I,

R = 110/3.5,
R = 31.42857142857143,
R = 31 OHM.

Srinivas said:   9 years ago
V = IR.
V = 110.
I = 3.5.
R = V/I = 110/3.5 = 31.

Mukesh Kumar Ghotra bemoth said:   9 years ago
V = lR.
R = v\l.
V = 110 v.
I = 3.5 A.
R =110\3.5 = 31.4 ohm.

Sarath said:   9 years ago
According to Ohm's law:

V = IR,

R = V/I,

R = 110/3.5,

R = 31.42.

JAGANNATH said:   9 years ago
According to ohm's law V = IR.
Then, I = V/R.
R = 110/3.5 = 31.4285.

Narendra Patil said:   9 years ago
Ohms law states that at constant temperature the current flowing through the conductor is directly proportional to potential different between the two end of the conductor.

That is V = IR.

Bhushan said:   9 years ago
What is the answer if there will be another option as. 31.5?

Imrosekhan said:   9 years ago
According to ohm's law v = IR.

Here we have to find resistance so, R = V/I.
Substitute those values=110/3.5 = 31.42.
But here they are taken as round figure value i.e 31.

Raj vendra said:   9 years ago
According to ohm'law v=IR.
R = v/I.


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