Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385 
38.5
3.1
31
Discussion:
102 comments Page 10 of 11.
Rupesh said:
1 decade ago
Why not the approximate answer is 31.1.
Jetendra patel said:
10 years ago
Absolutely right 110/3.5.
31.428 ohms.
31.428 ohms.
Raj vendra said:
9 years ago
According to ohm'law v=IR.
R = v/I.
R = v/I.
John lerr said:
2 years ago
R = V÷I.
R = 110÷3.5.
= 3.1 Ohms.
R = 110÷3.5.
= 3.1 Ohms.
(1)
Bibek said:
7 years ago
The correct answer is 31.4 Ω.
Reshma said:
1 decade ago
Ya its absolutely right.......
Er.Mukesh kumar said:
8 years ago
According yo law, 31 is right.
Sambathfire said:
1 decade ago
r=v/i
r=110/3.5
r=31.4
r=31
r=110/3.5
r=31.4
r=31
Magesh said:
8 years ago
Solve it by using ohm' law.
Sundaram.A said:
1 decade ago
R=V/I
=110/3.5
=31.4~31ohm
=110/3.5
=31.4~31ohm
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