Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 6)
6.
How much resistance is required to limit the current from a 12 V battery to 3.6 mA?
3.3 k
33 k
2.2 k
22 k
Discussion:
24 comments Page 1 of 3.
Densy said:
6 years ago
Exa (E) =10^18.
Peta(P)=10^15.
Tera(T)=10^12,
Giga(G)=10^9,
Mega(M)=10^6,
Kilo(K)=10^3,
Hecto(h)=10^2,
Deka(da)=10^1,
Deci(d)=10^-1,
Centi(c)=10^-2,
Milli(m)=10^-3,
Micro(mue)=10^-6,
Nano(n)=10^-9,
Pico(p)=10^-12,
Femto(f)=10^-15,
Atto(a) = 10^-18.
Peta(P)=10^15.
Tera(T)=10^12,
Giga(G)=10^9,
Mega(M)=10^6,
Kilo(K)=10^3,
Hecto(h)=10^2,
Deka(da)=10^1,
Deci(d)=10^-1,
Centi(c)=10^-2,
Milli(m)=10^-3,
Micro(mue)=10^-6,
Nano(n)=10^-9,
Pico(p)=10^-12,
Femto(f)=10^-15,
Atto(a) = 10^-18.
(7)
Ravi said:
1 decade ago
According to ohms law.
V = IxR.
R= V/I.
So data given.
V = 12V.
I = 3.6 mA.
R = V/I.
= 12/(3.6*10^-3).
= 12*10^3/3.6. (Here denominator 10^-3 shifted to numerator i.e 10^3).
= 12000/3.6.
= 3.3 kilo ohms.
V = IxR.
R= V/I.
So data given.
V = 12V.
I = 3.6 mA.
R = V/I.
= 12/(3.6*10^-3).
= 12*10^3/3.6. (Here denominator 10^-3 shifted to numerator i.e 10^3).
= 12000/3.6.
= 3.3 kilo ohms.
(3)
Vinay said:
1 decade ago
Ohm's Law :- V = I*R
But here we adjust the terms as,
R = V/I
= 12/3.6 * 10^-3 ...(^ sign is POWER )
= (12/3.6)* 10^3 ...(shifting of 10^-3)
= 3.3 * 10^3
R = 3.3 kilo-ohm
But here we adjust the terms as,
R = V/I
= 12/3.6 * 10^-3 ...(^ sign is POWER )
= (12/3.6)* 10^3 ...(shifting of 10^-3)
= 3.3 * 10^3
R = 3.3 kilo-ohm
Pramod shinva said:
1 decade ago
Over formula is suitable for only in Ohms Volts Amps. So we should be convert mA to Amps.(3.6MA = 3600A).
R = V/I.
= 12/3600.
= 0.0033ohms (0.0033ohms = 3.33 kohms).
= 3.3 kohms.
R = V/I.
= 12/3600.
= 0.0033ohms (0.0033ohms = 3.33 kohms).
= 3.3 kohms.
Imrosekhan said:
9 years ago
As we know that v = ir.
According to ohm's law.
So, R = V/I.
Substitute those values in the above equation.
we get, 12/10powerten(-3) = 3.3kiloohms.
According to ohm's law.
So, R = V/I.
Substitute those values in the above equation.
we get, 12/10powerten(-3) = 3.3kiloohms.
Appaso said:
10 years ago
All comments which are given above is totally wrong because ohms law given by them is totally wrong. i is directly proportional to v.
PROJIT SAHA said:
1 decade ago
ACCORDING TO OHM'S LAW,
R(resistance)=V(voltage)/I(current)
=12/3.6
=3.33 kilo-ohm
R(resistance)=V(voltage)/I(current)
=12/3.6
=3.33 kilo-ohm
Shahadat said:
1 decade ago
@Jayadhar you are right,
Because of Temperature is constant And
According to OHM's law,
V = RI.
R = 3.3 k ohm's.
Because of Temperature is constant And
According to OHM's law,
V = RI.
R = 3.3 k ohm's.
(1)
Tapaswini swain said:
1 decade ago
I=V/R
V=12V
I=3.6mA=3.6*10^-3
R=V/I
R=(12/36*10^-4)Ohm
=(1/3)*10^4ohm
=0.333*10^4ohm
=3.33*10^3ohm
=3.33kilo-ohm
V=12V
I=3.6mA=3.6*10^-3
R=V/I
R=(12/36*10^-4)Ohm
=(1/3)*10^4ohm
=0.333*10^4ohm
=3.33*10^3ohm
=3.33kilo-ohm
Jayadhar said:
1 decade ago
Assuming Temperature is constant, By OHM'S law,
V = RI.
hence; R= V/I.
R = 12/36000.
R = 3333.3333 ohms.
V = RI.
hence; R= V/I.
R = 12/36000.
R = 3333.3333 ohms.
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