Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 6)
6.
How much resistance is required to limit the current from a 12 V battery to 3.6 mA?
3.3 k
33 k
2.2 k
22 k
Discussion:
24 comments Page 2 of 3.
J.venkatesh said:
1 decade ago
According to ohms law,
V=IR
V=12v
I=3.6ma
R=V/I
I=0.0036AMPS.
R=12/0.036
FINALLY R=3300 OHMS.
R=3.3KOHMS.
V=IR
V=12v
I=3.6ma
R=V/I
I=0.0036AMPS.
R=12/0.036
FINALLY R=3300 OHMS.
R=3.3KOHMS.
Vikas kumar said:
1 decade ago
V=12, I = 3.6mA=0.0036A.
V=IR.
R=V/I=12/0.0036=12*10^4/36=10^4/3=10000/3=3333.33 ohm.
3.3 kilo ohm.
V=IR.
R=V/I=12/0.0036=12*10^4/36=10^4/3=10000/3=3333.33 ohm.
3.3 kilo ohm.
Prema said:
9 years ago
Can anyone let me know the conversation of (-3) to (+3)?
Anil said:
4 years ago
According to Ohms law;
R = V/I.
R = 12/3.6 = 3.33.
R = V/I.
R = 12/3.6 = 3.33.
(2)
Aakarsh Chandra said:
3 years ago
V = IR ,
R = V/I,
R = 12/0.36A,
R = 33.3 ohm.
R = V/I,
R = 12/0.36A,
R = 33.3 ohm.
(2)
Sunny said:
1 decade ago
V=12
I=3.6mA
R=12/3.6*10^-3=12/0.036=3.3kohms.
I=3.6mA
R=12/3.6*10^-3=12/0.036=3.3kohms.
Mani said:
1 decade ago
I want range of mA and killo-ohm. Any one say?
AVATAR said:
1 decade ago
R = V/I.
SO, R = 12/3.6 = 3.333333333333333.
SO, R = 12/3.6 = 3.333333333333333.
Johnlerr Espenoza said:
2 years ago
R = V÷I.
R = 12÷3.6.
= 3.3Ohms.
R = 12÷3.6.
= 3.3Ohms.
(3)
Suraj said:
1 decade ago
Absolutely its 3.33kilo ohms.
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