Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 6)
6.
How much resistance is required to limit the current from a 12 V battery to 3.6 mA?
3.3 k
33 k
2.2 k
22 k
Discussion:
24 comments Page 3 of 3.
Makhado said:
6 years ago
Thank you all for explaining.
(1)
Surekha said:
1 decade ago
mA=10^-3
kilo ohm =10^3
kilo ohm =10^3
Sakthi said:
1 decade ago
V=I/R
V=12/3.6
V=3.3KM
V=12/3.6
V=3.3KM
Anand said:
1 decade ago
Nice answer vinay
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