Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 6)
6.
How much resistance is required to limit the current from a 12 V battery to 3.6 mA?
3.3 k
33 k
2.2 k
22 k
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
24 comments Page 1 of 3.

Johnlerr Espenoza said:   2 years ago
R = V÷I.
R = 12÷3.6.
= 3.3Ohms.
(3)

Aakarsh Chandra said:   3 years ago
V = IR ,
R = V/I,
R = 12/0.36A,
R = 33.3 ohm.
(2)

Anil said:   4 years ago
According to Ohms law;

R = V/I.
R = 12/3.6 = 3.33.
(2)

Densy said:   6 years ago
Exa (E) =10^18.
Peta(P)=10^15.
Tera(T)=10^12,
Giga(G)=10^9,
Mega(M)=10^6,
Kilo(K)=10^3,
Hecto(h)=10^2,
Deka(da)=10^1,
Deci(d)=10^-1,
Centi(c)=10^-2,
Milli(m)=10^-3,
Micro(mue)=10^-6,
Nano(n)=10^-9,
Pico(p)=10^-12,
Femto(f)=10^-15,
Atto(a) = 10^-18.
(7)

Makhado said:   6 years ago
Thank you all for explaining.
(1)

Prema said:   9 years ago
Can anyone let me know the conversation of (-3) to (+3)?

Imrosekhan said:   9 years ago
As we know that v = ir.
According to ohm's law.
So, R = V/I.

Substitute those values in the above equation.
we get, 12/10powerten(-3) = 3.3kiloohms.

Appaso said:   10 years ago
All comments which are given above is totally wrong because ohms law given by them is totally wrong. i is directly proportional to v.

Ravi said:   1 decade ago
According to ohms law.

V = IxR.
R= V/I.

So data given.

V = 12V.
I = 3.6 mA.

R = V/I.

= 12/(3.6*10^-3).

= 12*10^3/3.6. (Here denominator 10^-3 shifted to numerator i.e 10^3).

= 12000/3.6.

= 3.3 kilo ohms.
(3)

AVATAR said:   1 decade ago
R = V/I.

SO, R = 12/3.6 = 3.333333333333333.


Post your comments here:

Your comments will be displayed after verification.