# Electrical Engineering - Ohm's Law - Discussion

### Discussion :: Ohm's Law - General Questions (Q.No.6)

6.

How much resistance is required to limit the current from a 12 V battery to 3.6 mA?

 [A]. 3.3 k [B]. 33 k [C]. 2.2 k [D]. 22 k Explanation:

No answer description available for this question.

 Projit Saha said: (Jan 20, 2011) ACCORDING TO OHM'S LAW, R(resistance)=V(voltage)/I(current) =12/3.6 =3.33 kilo-ohm

 Vinay said: (Feb 23, 2011) Ohm's Law :- V = I*R But here we adjust the terms as, R = V/I = 12/3.6 * 10^-3 ...(^ sign is POWER ) = (12/3.6)* 10^3 ...(shifting of 10^-3) = 3.3 * 10^3 R = 3.3 kilo-ohm

 Mani said: (Mar 13, 2011) I want range of mA and killo-ohm. Any one say?

 Surekha said: (Jul 10, 2011) mA=10^-3 kilo ohm =10^3

 Sakthi said: (Jul 12, 2011) V=I/R V=12/3.6 V=3.3KM

 Anand said: (Jul 22, 2011) Nice answer vinay

 Suraj said: (Sep 20, 2011) Absolutely its 3.33kilo ohms.

 Tapaswini Swain said: (Oct 15, 2011) I=V/R V=12V I=3.6mA=3.6*10^-3 R=V/I R=(12/36*10^-4)Ohm =(1/3)*10^4ohm =0.333*10^4ohm =3.33*10^3ohm =3.33kilo-ohm

 Vikas Kumar said: (Jul 19, 2012) V=12, I = 3.6mA=0.0036A. V=IR. R=V/I=12/0.0036=12*10^4/36=10^4/3=10000/3=3333.33 ohm. 3.3 kilo ohm.

 Sunny said: (Aug 27, 2012) V=12 I=3.6mA R=12/3.6*10^-3=12/0.036=3.3kohms.

 J.Venkatesh said: (Oct 14, 2012) According to ohms law, V=IR V=12v I=3.6ma R=V/I I=0.0036AMPS. R=12/0.036 FINALLY R=3300 OHMS. R=3.3KOHMS.

 Pramod Shinva said: (Aug 4, 2013) Over formula is suitable for only in Ohms Volts Amps. So we should be convert mA to Amps.(3.6MA = 3600A). R = V/I. = 12/3600. = 0.0033ohms (0.0033ohms = 3.33 kohms). = 3.3 kohms.

 Jayadhar said: (Sep 22, 2013) Assuming Temperature is constant, By OHM'S law, V = RI. hence; R= V/I. R = 12/36000. R = 3333.3333 ohms.

 Shahadat said: (Oct 3, 2013) @Jayadhar you are right, Because of Temperature is constant And According to OHM's law, V = RI. R = 3.3 k ohm's.

 Avatar said: (Oct 8, 2014) R = V/I. SO, R = 12/3.6 = 3.333333333333333.

 Ravi said: (Aug 22, 2015) According to ohms law. V = IxR. R= V/I. So data given. V = 12V. I = 3.6 mA. R = V/I. = 12/(3.6*10^-3). = 12*10^3/3.6. (Here denominator 10^-3 shifted to numerator i.e 10^3). = 12000/3.6. = 3.3 kilo ohms.

 Appaso said: (Nov 10, 2015) All comments which are given above is totally wrong because ohms law given by them is totally wrong. i is directly proportional to v.

 Imrosekhan said: (Nov 16, 2016) As we know that v = ir. According to ohm's law. So, R = V/I. Substitute those values in the above equation. we get, 12/10powerten(-3) = 3.3kiloohms.

 Prema said: (Mar 9, 2017) Can anyone let me know the conversation of (-3) to (+3)?

 Makhado said: (Jul 22, 2019) Thank you all for explaining.

 Densy said: (Feb 6, 2020) Exa (E) =10^18. Peta(P)=10^15. Tera(T)=10^12, Giga(G)=10^9, Mega(M)=10^6, Kilo(K)=10^3, Hecto(h)=10^2, Deka(da)=10^1, Deci(d)=10^-1, Centi(c)=10^-2, Milli(m)=10^-3, Micro(mue)=10^-6, Nano(n)=10^-9, Pico(p)=10^-12, Femto(f)=10^-15, Atto(a) = 10^-18.

 Anil said: (May 19, 2021) According to Ohms law; R = V/I. R = 12/3.6 = 3.33.