Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 6)
6.
How much resistance is required to limit the current from a 12 V battery to 3.6 mA?
3.3 k
33 k
2.2 k
22 k
Discussion:
24 comments Page 3 of 3.
Surekha said:
1 decade ago
mA=10^-3
kilo ohm =10^3
kilo ohm =10^3
Mani said:
1 decade ago
I want range of mA and killo-ohm. Any one say?
Vinay said:
1 decade ago
Ohm's Law :- V = I*R
But here we adjust the terms as,
R = V/I
= 12/3.6 * 10^-3 ...(^ sign is POWER )
= (12/3.6)* 10^3 ...(shifting of 10^-3)
= 3.3 * 10^3
R = 3.3 kilo-ohm
But here we adjust the terms as,
R = V/I
= 12/3.6 * 10^-3 ...(^ sign is POWER )
= (12/3.6)* 10^3 ...(shifting of 10^-3)
= 3.3 * 10^3
R = 3.3 kilo-ohm
PROJIT SAHA said:
1 decade ago
ACCORDING TO OHM'S LAW,
R(resistance)=V(voltage)/I(current)
=12/3.6
=3.33 kilo-ohm
R(resistance)=V(voltage)/I(current)
=12/3.6
=3.33 kilo-ohm
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