Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 4)
4.
A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?
Discussion:
29 comments Page 3 of 3.
Gopi said:
1 decade ago
Kwh = (350*24*24)/1000
= 201.6kWh
= 201.6kWh
Rajesh said:
1 decade ago
For 540w
(540*24*26)/1000=336.96kwh
(540*24*26)/1000=336.96kwh
Hirdesh Pal said:
1 decade ago
Gopi you are right & thank you.
Md Kaium said:
5 years ago
KWh= (350*24*24)/1000
=201.6kwh.
=201.6kwh.
(3)
Sstyam said:
8 years ago
You are correct, Thanks @Gopi.
Sham said:
9 years ago
Thank you @Pramod Shinva.
Mahantesh said:
8 years ago
201.6kwh is correct.
Sush said:
1 decade ago
Gopi is correct.
Balu said:
1 decade ago
Correct.
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