Electrical Engineering - Energy and Power - Discussion

Discussion Forum : Energy and Power - General Questions (Q.No. 4)
4.
A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?
20.16 kWh
201.6 kWh
2.01 kWh
8.4 kWh
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
29 comments Page 3 of 3.

Gopi said:   1 decade ago
Kwh = (350*24*24)/1000
= 201.6kWh

Rajesh said:   1 decade ago
For 540w
(540*24*26)/1000=336.96kwh

Hirdesh Pal said:   1 decade ago
Gopi you are right & thank you.

Md Kaium said:   5 years ago
KWh= (350*24*24)/1000
=201.6kwh.
(3)

Sstyam said:   8 years ago
You are correct, Thanks @Gopi.

Sham said:   9 years ago
Thank you @Pramod Shinva.

Mahantesh said:   8 years ago
201.6kwh is correct.

Sush said:   1 decade ago
Gopi is correct.

Balu said:   1 decade ago
Correct.


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