Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 1)
1.
If the rms voltage drop across a 15 k
resistor is 16 V, the peak current through the resistor is
resistor is 16 V, the peak current through the resistor isDiscussion:
27 comments Page 1 of 3.
Gopi said:
1 decade ago
Erms = 16v.
R = 15Kohms = 15*10^3 = 15000.
We have Erms = Irms*R.
Irms = Erms/R.
= 16/15000.
= 0.001066A.
We have Irms = Imax/1.414.
Imax = Irms*1.414.
= 0.001066*1.414.
= 0.0015A = 1.5mA.
R = 15Kohms = 15*10^3 = 15000.
We have Erms = Irms*R.
Irms = Erms/R.
= 16/15000.
= 0.001066A.
We have Irms = Imax/1.414.
Imax = Irms*1.414.
= 0.001066*1.414.
= 0.0015A = 1.5mA.
Dino said:
1 decade ago
Emax = 16 V/0.707.
Emax = 22.63 V or 22V.
I = V/R.
I = 22 V/ 15 kΩ.
to convert 15 kΩ to ohms.
15 kΩ * 1000 Ω/1 kΩ.
I= 22 V/ 15000 Ω.
I= 1.46 mA or 1.5 mA.
Emax = 22.63 V or 22V.
I = V/R.
I = 22 V/ 15 kΩ.
to convert 15 kΩ to ohms.
15 kΩ * 1000 Ω/1 kΩ.
I= 22 V/ 15000 Ω.
I= 1.46 mA or 1.5 mA.
PREETHAM CHANDRA said:
9 years ago
WKT Vrms = 0.707Vmax => Here Vrms = 16v.
16 = 0.707 * Vmax = >
Vmax = 16/0.707=> 22.6308v.
So, Imax=Vmax / R=> 22.6308/15K = 1.508mA.
16 = 0.707 * Vmax = >
Vmax = 16/0.707=> 22.6308v.
So, Imax=Vmax / R=> 22.6308/15K = 1.508mA.
Dollar said:
4 years ago
V = 16.
R = 15000.
Irms = 16/15000.
= 0.001067A,
= 1.067mA.
Im = Irms/0.707.
= 1.067/0.707.
= 1.5mA.
R = 15000.
Irms = 16/15000.
= 0.001067A,
= 1.067mA.
Im = Irms/0.707.
= 1.067/0.707.
= 1.5mA.
(6)
Aamir sohail said:
1 decade ago
Sample,
Imax = Irms*1.414
Irms = V/R
V=16, R=15 k=15000.
Irms = 16/15000 = 0.001067A = 1.067mA.
Imax = 1.067*1.414 = 1.5mA.
Imax = Irms*1.414
Irms = V/R
V=16, R=15 k=15000.
Irms = 16/15000 = 0.001067A = 1.067mA.
Imax = 1.067*1.414 = 1.5mA.
Rajesh said:
1 decade ago
Here giving,
V = 15 v.
And R = 15000.
Then we know that Im = 2^1/2 Irms.
And Irms = V/R and solving it find Im = 1.5 mA.
V = 15 v.
And R = 15000.
Then we know that Im = 2^1/2 Irms.
And Irms = V/R and solving it find Im = 1.5 mA.
Nafish said:
1 decade ago
It as simple as.....
V=16
R=15k = 15000
Irms= V/R = 16/15000 = 0.001067A = 1.067mA
Imax=1.414*1.067mA = 1.51mA
V=16
R=15k = 15000
Irms= V/R = 16/15000 = 0.001067A = 1.067mA
Imax=1.414*1.067mA = 1.51mA
GANGA RAM GAUTAM said:
1 decade ago
V = 15V.
R = 15000.
Irms = V/R = 16/15000.
= 0.001067A.
Imax = 1.414x1.067mA.
= 1.51mA.
R = 15000.
Irms = V/R = 16/15000.
= 0.001067A.
Imax = 1.414x1.067mA.
= 1.51mA.
Naiyar said:
1 decade ago
Can someone please explain the concept of phase voltage, phase current and line voltage and current.
Sunil kumar said:
1 decade ago
rms voltage = 16 volts.
max voltage = 16*1.414= 22.62 volts.
I=V/R =22.62/15000 = 1.5 mA.
max voltage = 16*1.414= 22.62 volts.
I=V/R =22.62/15000 = 1.5 mA.
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