Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 1)
1.
If the rms voltage drop across a 15 k
resistor is 16 V, the peak current through the resistor is
resistor is 16 V, the peak current through the resistor isDiscussion:
27 comments Page 2 of 3.
Ayush said:
1 decade ago
V=16
R=15k = 15000
Irms= V/R = 16/15000 = 0.001067A = 1.067mA
Imax=1.414*1.067mA = 1.51mA
R=15k = 15000
Irms= V/R = 16/15000 = 0.001067A = 1.067mA
Imax=1.414*1.067mA = 1.51mA
Keerthi said:
1 decade ago
vrms=vm/1.414
so given vrms=16
hence vm=16*1.414
vm=22.6 v
im=vm/r
im=22.6/15k
im=1.5mA
so given vrms=16
hence vm=16*1.414
vm=22.6 v
im=vm/r
im=22.6/15k
im=1.5mA
Lakmal said:
1 decade ago
Please Anyone answer me. In which level This questions are include? In Diploma level?
Yuvraj said:
1 decade ago
Irms=Vrms/15k=1.066 ma
now Ipeak=Irms*sqrt(2)
therefore, Ipeak= 1.066*1.414 =1.5 ma
now Ipeak=Irms*sqrt(2)
therefore, Ipeak= 1.066*1.414 =1.5 ma
Nikita said:
1 decade ago
Vpeak = 1.414 * Vrms = 1.414*16 = 22.624.
Ipeak = Vpeak/R = 22.624/15000 = 1.5mA.
Ipeak = Vpeak/R = 22.624/15000 = 1.5mA.
DHARMA said:
1 decade ago
Mr @Rajesh said that v=15v. Then how he calculated and answer also 1. 5mA. HOW?
Naveen said:
1 decade ago
V= 16
R= 15oo0
Irms= 16/15000
Im= Irms/0.707
= 16/(15000*0.707)
= 1.5 mA
R= 15oo0
Irms= 16/15000
Im= Irms/0.707
= 16/(15000*0.707)
= 1.5 mA
GANESH said:
1 decade ago
Irms = Io/1.414.
Io = Eo/R=16/15mA.
Irms = 16*0.707/15mA = 1.5mA.
Io = Eo/R=16/15mA.
Irms = 16*0.707/15mA = 1.5mA.
Skh said:
1 decade ago
Vrms = 16v.
Vmax = Vrms*1.414.
Imax = Vmax/r.
Imax = 1.5mA.
Vmax = Vrms*1.414.
Imax = Vmax/r.
Imax = 1.5mA.
Rakesh kumar said:
1 decade ago
im=2^1/2*(irms)
irms=v/r
=16/15k
im=2^1/2*(16/15k)
=1.51ma
irms=v/r
=16/15k
im=2^1/2*(16/15k)
=1.51ma
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