# Electrical Engineering - Alternating Current and Voltage - Discussion

### Discussion :: Alternating Current and Voltage - General Questions (Q.No.1)

1.

If the rms voltage drop across a 15 k resistor is 16 V, the peak current through the resistor is

 [A]. 15 mA [B]. 1.5 mA [C]. 10 mA [D]. 1 mA

Explanation:

No answer description available for this question.

 Naveen said: (Dec 18, 2010) V= 16 R= 15oo0 Irms= 16/15000 Im= Irms/0.707 = 16/(15000*0.707) = 1.5 mA

 Rokon said: (Jan 5, 2011) (RMS x 1.414) x 2=P-P

 Nafish said: (Mar 2, 2011) It as simple as..... V=16 R=15k = 15000 Irms= V/R = 16/15000 = 0.001067A = 1.067mA Imax=1.414*1.067mA = 1.51mA

 Keerthi said: (May 23, 2011) vrms=vm/1.414 so given vrms=16 hence vm=16*1.414 vm=22.6 v im=vm/r im=22.6/15k im=1.5mA

 Rakesh Kumar said: (Aug 29, 2011) im=2^1/2*(irms) irms=v/r =16/15k im=2^1/2*(16/15k) =1.51ma

 Yuvraj said: (Sep 22, 2012) Irms=Vrms/15k=1.066 ma now Ipeak=Irms*sqrt(2) therefore, Ipeak= 1.066*1.414 =1.5 ma

 Ayush said: (Oct 8, 2012) V=16 R=15k = 15000 Irms= V/R = 16/15000 = 0.001067A = 1.067mA Imax=1.414*1.067mA = 1.51mA

 Rajesh said: (Jun 15, 2013) Here giving, V = 15 v. And R = 15000. Then we know that Im = 2^1/2 Irms. And Irms = V/R and solving it find Im = 1.5 mA.

 Dharma said: (Jul 29, 2013) Mr @Rajesh said that v=15v. Then how he calculated and answer also 1. 5mA. HOW?

 Lakmal said: (Aug 8, 2013) Please Anyone answer me. In which level This questions are include? In Diploma level?

 Ganga Ram Gautam said: (Dec 14, 2013) V = 15V. R = 15000. Irms = V/R = 16/15000. = 0.001067A. Imax = 1.414x1.067mA. = 1.51mA.

 Sunil Kumar said: (Feb 22, 2014) rms voltage = 16 volts. max voltage = 16*1.414= 22.62 volts. I=V/R =22.62/15000 = 1.5 mA.

 Nikita said: (Feb 26, 2014) Vpeak = 1.414 * Vrms = 1.414*16 = 22.624. Ipeak = Vpeak/R = 22.624/15000 = 1.5mA.

 Dino said: (Mar 19, 2014) Emax = 16 V/0.707. Emax = 22.63 V or 22V. I = V/R. I = 22 V/ 15 kΩ. to convert 15 kΩ to ohms. 15 kΩ * 1000 Ω/1 kΩ. I= 22 V/ 15000 Ω. I= 1.46 mA or 1.5 mA.

 Gopi said: (Mar 24, 2014) Erms = 16v. R = 15Kohms = 15*10^3 = 15000. We have Erms = Irms*R. Irms = Erms/R. = 16/15000. = 0.001066A. We have Irms = Imax/1.414. Imax = Irms*1.414. = 0.001066*1.414. = 0.0015A = 1.5mA.

 Ganesh said: (May 6, 2014) Irms = Io/1.414. Io = Eo/R=16/15mA. Irms = 16*0.707/15mA = 1.5mA.

 Aamir Sohail said: (May 13, 2014) Sample, Imax = Irms*1.414 Irms = V/R V=16, R=15 k=15000. Irms = 16/15000 = 0.001067A = 1.067mA. Imax = 1.067*1.414 = 1.5mA.

 Subash Pakhrin said: (Jul 12, 2014) Simple. Irms = Imax/root(2). Use this formula.

 Naiyar said: (Aug 18, 2014) Can someone please explain the concept of phase voltage, phase current and line voltage and current.

 Skh said: (Aug 7, 2015) Vrms = 16v. Vmax = Vrms*1.414. Imax = Vmax/r. Imax = 1.5mA.

 Sameed said: (Nov 4, 2015) Good question about basics.

 Preetham Chandra said: (Dec 21, 2016) WKT Vrms = 0.707Vmax => Here Vrms = 16v. 16 = 0.707 * Vmax = > Vmax = 16/0.707=> 22.6308v. So, Imax=Vmax / R=> 22.6308/15K = 1.508mA.

 Basavaraj said: (Jun 26, 2017) Imax= 1.414*irms 1.414*16/15k=1.50ma.

 Vengatesh said: (Feb 4, 2018) What is rms?

 D.Jyothi said: (Aug 30, 2018) Vrms\Vavg=form factor=1.1. Vmax/Vrms=peak factor=1.414.

 Rishi said: (Nov 25, 2018) Here, it is (16*1.414)/(15*1000).