Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion :: Alternating Current and Voltage - General Questions (Q.No.1)

1. 

If the rms voltage drop across a 15 k resistor is 16 V, the peak current through the resistor is

[A]. 15 mA
[B]. 1.5 mA
[C]. 10 mA
[D]. 1 mA

Answer: Option B

Explanation:

No answer description available for this question.

Naveen said: (Dec 18, 2010)  
V= 16
R= 15oo0
Irms= 16/15000
Im= Irms/0.707
= 16/(15000*0.707)
= 1.5 mA

Rokon said: (Jan 5, 2011)  
(RMS x 1.414) x 2=P-P

Nafish said: (Mar 2, 2011)  
It as simple as.....
V=16
R=15k = 15000
Irms= V/R = 16/15000 = 0.001067A = 1.067mA
Imax=1.414*1.067mA = 1.51mA

Keerthi said: (May 23, 2011)  
vrms=vm/1.414
so given vrms=16
hence vm=16*1.414
vm=22.6 v
im=vm/r
im=22.6/15k
im=1.5mA

Rakesh Kumar said: (Aug 29, 2011)  
im=2^1/2*(irms)
irms=v/r
=16/15k
im=2^1/2*(16/15k)
=1.51ma

Yuvraj said: (Sep 22, 2012)  
Irms=Vrms/15k=1.066 ma
now Ipeak=Irms*sqrt(2)

therefore, Ipeak= 1.066*1.414 =1.5 ma

Ayush said: (Oct 8, 2012)  
V=16
R=15k = 15000
Irms= V/R = 16/15000 = 0.001067A = 1.067mA
Imax=1.414*1.067mA = 1.51mA

Rajesh said: (Jun 15, 2013)  
Here giving,

V = 15 v.
And R = 15000.

Then we know that Im = 2^1/2 Irms.

And Irms = V/R and solving it find Im = 1.5 mA.

Dharma said: (Jul 29, 2013)  
Mr @Rajesh said that v=15v. Then how he calculated and answer also 1. 5mA. HOW?

Lakmal said: (Aug 8, 2013)  
Please Anyone answer me. In which level This questions are include? In Diploma level?

Ganga Ram Gautam said: (Dec 14, 2013)  
V = 15V.
R = 15000.

Irms = V/R = 16/15000.
= 0.001067A.

Imax = 1.414x1.067mA.
= 1.51mA.

Sunil Kumar said: (Feb 22, 2014)  
rms voltage = 16 volts.

max voltage = 16*1.414= 22.62 volts.

I=V/R =22.62/15000 = 1.5 mA.

Nikita said: (Feb 26, 2014)  
Vpeak = 1.414 * Vrms = 1.414*16 = 22.624.

Ipeak = Vpeak/R = 22.624/15000 = 1.5mA.

Dino said: (Mar 19, 2014)  
Emax = 16 V/0.707.

Emax = 22.63 V or 22V.

I = V/R.

I = 22 V/ 15 kΩ.

to convert 15 kΩ to ohms.

15 kΩ * 1000 Ω/1 kΩ.

I= 22 V/ 15000 Ω.

I= 1.46 mA or 1.5 mA.

Gopi said: (Mar 24, 2014)  
Erms = 16v.
R = 15Kohms = 15*10^3 = 15000.
We have Erms = Irms*R.
Irms = Erms/R.
= 16/15000.
= 0.001066A.

We have Irms = Imax/1.414.

Imax = Irms*1.414.
= 0.001066*1.414.
= 0.0015A = 1.5mA.

Ganesh said: (May 6, 2014)  
Irms = Io/1.414.
Io = Eo/R=16/15mA.
Irms = 16*0.707/15mA = 1.5mA.

Aamir Sohail said: (May 13, 2014)  
Sample,

Imax = Irms*1.414
Irms = V/R
V=16, R=15 k=15000.

Irms = 16/15000 = 0.001067A = 1.067mA.
Imax = 1.067*1.414 = 1.5mA.

Subash Pakhrin said: (Jul 12, 2014)  
Simple.

Irms = Imax/root(2).

Use this formula.

Naiyar said: (Aug 18, 2014)  
Can someone please explain the concept of phase voltage, phase current and line voltage and current.

Skh said: (Aug 7, 2015)  
Vrms = 16v.
Vmax = Vrms*1.414.

Imax = Vmax/r.
Imax = 1.5mA.

Sameed said: (Nov 4, 2015)  
Good question about basics.

Preetham Chandra said: (Dec 21, 2016)  
WKT Vrms = 0.707Vmax => Here Vrms = 16v.

16 = 0.707 * Vmax = >
Vmax = 16/0.707=> 22.6308v.

So, Imax=Vmax / R=> 22.6308/15K = 1.508mA.

Basavaraj said: (Jun 26, 2017)  
Imax= 1.414*irms 1.414*16/15k=1.50ma.

Vengatesh said: (Feb 4, 2018)  
What is rms?

D.Jyothi said: (Aug 30, 2018)  
Vrms\Vavg=form factor=1.1.

Vmax/Vrms=peak factor=1.414.

Rishi said: (Nov 25, 2018)  
Here, it is (16*1.414)/(15*1000).

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