Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 1)
1.
If the rms voltage drop across a 15 k resistor is 16 V, the peak current through the resistor is
15 mA
1.5 mA
10 mA
1 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 1 of 3.

Dollar said:   4 years ago
V = 16.
R = 15000.
Irms = 16/15000.
= 0.001067A,
= 1.067mA.
Im = Irms/0.707.
= 1.067/0.707.
= 1.5mA.
(6)

Rishi said:   7 years ago
Here, it is (16*1.414)/(15*1000).
(2)

D.Jyothi said:   7 years ago
Vrms\Vavg=form factor=1.1.

Vmax/Vrms=peak factor=1.414.

Vengatesh said:   8 years ago
What is rms?

Basavaraj said:   8 years ago
Imax= 1.414*irms 1.414*16/15k=1.50ma.
(2)

PREETHAM CHANDRA said:   9 years ago
WKT Vrms = 0.707Vmax => Here Vrms = 16v.

16 = 0.707 * Vmax = >
Vmax = 16/0.707=> 22.6308v.

So, Imax=Vmax / R=> 22.6308/15K = 1.508mA.

Sameed said:   10 years ago
Good question about basics.

Skh said:   1 decade ago
Vrms = 16v.
Vmax = Vrms*1.414.

Imax = Vmax/r.
Imax = 1.5mA.

Naiyar said:   1 decade ago
Can someone please explain the concept of phase voltage, phase current and line voltage and current.

Subash pakhrin said:   1 decade ago
Simple.

Irms = Imax/root(2).

Use this formula.
(1)


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