Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 1)
1.
If the rms voltage drop across a 15 k
resistor is 16 V, the peak current through the resistor is
resistor is 16 V, the peak current through the resistor isDiscussion:
27 comments Page 1 of 3.
Dollar said:
4 years ago
V = 16.
R = 15000.
Irms = 16/15000.
= 0.001067A,
= 1.067mA.
Im = Irms/0.707.
= 1.067/0.707.
= 1.5mA.
R = 15000.
Irms = 16/15000.
= 0.001067A,
= 1.067mA.
Im = Irms/0.707.
= 1.067/0.707.
= 1.5mA.
(6)
Rishi said:
7 years ago
Here, it is (16*1.414)/(15*1000).
(2)
Basavaraj said:
8 years ago
Imax= 1.414*irms 1.414*16/15k=1.50ma.
(2)
Subash pakhrin said:
1 decade ago
Simple.
Irms = Imax/root(2).
Use this formula.
Irms = Imax/root(2).
Use this formula.
(1)
Dino said:
1 decade ago
Emax = 16 V/0.707.
Emax = 22.63 V or 22V.
I = V/R.
I = 22 V/ 15 kΩ.
to convert 15 kΩ to ohms.
15 kΩ * 1000 Ω/1 kΩ.
I= 22 V/ 15000 Ω.
I= 1.46 mA or 1.5 mA.
Emax = 22.63 V or 22V.
I = V/R.
I = 22 V/ 15 kΩ.
to convert 15 kΩ to ohms.
15 kΩ * 1000 Ω/1 kΩ.
I= 22 V/ 15000 Ω.
I= 1.46 mA or 1.5 mA.
D.Jyothi said:
7 years ago
Vrms\Vavg=form factor=1.1.
Vmax/Vrms=peak factor=1.414.
Vmax/Vrms=peak factor=1.414.
Vengatesh said:
8 years ago
What is rms?
PREETHAM CHANDRA said:
9 years ago
WKT Vrms = 0.707Vmax => Here Vrms = 16v.
16 = 0.707 * Vmax = >
Vmax = 16/0.707=> 22.6308v.
So, Imax=Vmax / R=> 22.6308/15K = 1.508mA.
16 = 0.707 * Vmax = >
Vmax = 16/0.707=> 22.6308v.
So, Imax=Vmax / R=> 22.6308/15K = 1.508mA.
Sameed said:
10 years ago
Good question about basics.
Skh said:
1 decade ago
Vrms = 16v.
Vmax = Vrms*1.414.
Imax = Vmax/r.
Imax = 1.5mA.
Vmax = Vrms*1.414.
Imax = Vmax/r.
Imax = 1.5mA.
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