Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 1)
1.
If the rms voltage drop across a 15 k resistor is 16 V, the peak current through the resistor is
15 mA
1.5 mA
10 mA
1 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 2 of 3.

Naiyar said:   1 decade ago
Can someone please explain the concept of phase voltage, phase current and line voltage and current.

Aamir sohail said:   1 decade ago
Sample,

Imax = Irms*1.414
Irms = V/R
V=16, R=15 k=15000.

Irms = 16/15000 = 0.001067A = 1.067mA.
Imax = 1.067*1.414 = 1.5mA.

GANESH said:   1 decade ago
Irms = Io/1.414.
Io = Eo/R=16/15mA.
Irms = 16*0.707/15mA = 1.5mA.

Gopi said:   1 decade ago
Erms = 16v.
R = 15Kohms = 15*10^3 = 15000.
We have Erms = Irms*R.
Irms = Erms/R.
= 16/15000.
= 0.001066A.

We have Irms = Imax/1.414.

Imax = Irms*1.414.
= 0.001066*1.414.
= 0.0015A = 1.5mA.

Naveen said:   1 decade ago
V= 16
R= 15oo0
Irms= 16/15000
Im= Irms/0.707
= 16/(15000*0.707)
= 1.5 mA

Nikita said:   1 decade ago
Vpeak = 1.414 * Vrms = 1.414*16 = 22.624.

Ipeak = Vpeak/R = 22.624/15000 = 1.5mA.

Sunil kumar said:   1 decade ago
rms voltage = 16 volts.

max voltage = 16*1.414= 22.62 volts.

I=V/R =22.62/15000 = 1.5 mA.

GANGA RAM GAUTAM said:   1 decade ago
V = 15V.
R = 15000.

Irms = V/R = 16/15000.
= 0.001067A.

Imax = 1.414x1.067mA.
= 1.51mA.

Lakmal said:   1 decade ago
Please Anyone answer me. In which level This questions are include? In Diploma level?

DHARMA said:   1 decade ago
Mr @Rajesh said that v=15v. Then how he calculated and answer also 1. 5mA. HOW?


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