Digital Electronics - Flip-Flops - Discussion
Discussion Forum : Flip-Flops - General Questions (Q.No. 6)
6.
How many flip-flops are required to produce a divide-by-128 device?
Discussion:
16 comments Page 1 of 2.
Sachin bhardwaj said:
6 years ago
Thanks all for explaining.
Kundan mani said:
7 years ago
2^6=64. So we need 6 flip-flops.
SUMASRI said:
7 years ago
The no of flip-flops required is 7 because,
2^n=128,
=>2^n=2^7,
=>n=7,
Hence we require 7 flipflops.
2^n=128,
=>2^n=2^7,
=>n=7,
Hence we require 7 flipflops.
Riya said:
7 years ago
6 is correct because 2^n=64, No.of flip flops = n.
(1)
Ranjitha v said:
8 years ago
I think 7. This is no series count value of (1 2 4 8 16 32 64) -2^7=64.
Saieswari said:
8 years ago
How many flip flops are needed to divide the input frequency by 64 device?
(1)
Viki said:
9 years ago
It is multiplexer @Mani Shanker.
Mani shanker bhardwaj said:
9 years ago
Which of the following circuit is a parallel to serial converter?
A) digital counter
B) decoder
C) demultiplexer
D) multiplexer
Please give me the answer.
A) digital counter
B) decoder
C) demultiplexer
D) multiplexer
Please give me the answer.
Vipul Prajapati said:
9 years ago
Correct, but if there is suppose 10 then what will be the answer?
Abubakar maliki said:
1 decade ago
Even if we take 2>7 it will still give 128 so the flip-flops required are 7.
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