Digital Electronics - Flip-Flops - Discussion
Discussion Forum : Flip-Flops - General Questions (Q.No. 6)
6.
How many flip-flops are required to produce a divide-by-128 device?
Discussion:
16 comments Page 2 of 2.
Puja said:
1 decade ago
No.of flip flops = 2^n.
According that formula 2^7=128 is correct.
So, required flip flop is 7.
According that formula 2^7=128 is correct.
So, required flip flop is 7.
Thanusha said:
1 decade ago
2^(n-1)< N <2^n. [Here N=128].
Since given that it's a divide by 128 device. 2^n > 127 {because the flip flops could count from 0 to given no-1 i.e, 0 to 128-1=127}..
Therefore. =7.. where n is the no of flip flops necessary.
Since given that it's a divide by 128 device. 2^n > 127 {because the flip flops could count from 0 to given no-1 i.e, 0 to 128-1=127}..
Therefore. =7.. where n is the no of flip flops necessary.
Csk said:
1 decade ago
128 equal to 2 power n where n is the number of flip flops.....
Khaja said:
1 decade ago
Even if there is 127 it is less than 128(2^7) and more than 64 (2^6). So the number of flip flop requires will be the same 7.
Shyam gupta said:
1 decade ago
Correct but if there is 127 then what we do. ?
Pratyusha said:
1 decade ago
2^7 =128
=> 7 flip flops are required.
=> 7 flip flops are required.
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