Digital Electronics - Flip-Flops - Discussion
Discussion Forum : Flip-Flops - General Questions (Q.No. 6)
6.
How many flip-flops are required to produce a divide-by-128 device?
Discussion:
16 comments Page 1 of 2.
Thanusha said:
1 decade ago
2^(n-1)< N <2^n. [Here N=128].
Since given that it's a divide by 128 device. 2^n > 127 {because the flip flops could count from 0 to given no-1 i.e, 0 to 128-1=127}..
Therefore. =7.. where n is the no of flip flops necessary.
Since given that it's a divide by 128 device. 2^n > 127 {because the flip flops could count from 0 to given no-1 i.e, 0 to 128-1=127}..
Therefore. =7.. where n is the no of flip flops necessary.
Mani shanker bhardwaj said:
9 years ago
Which of the following circuit is a parallel to serial converter?
A) digital counter
B) decoder
C) demultiplexer
D) multiplexer
Please give me the answer.
A) digital counter
B) decoder
C) demultiplexer
D) multiplexer
Please give me the answer.
Khaja said:
1 decade ago
Even if there is 127 it is less than 128(2^7) and more than 64 (2^6). So the number of flip flop requires will be the same 7.
SUMASRI said:
7 years ago
The no of flip-flops required is 7 because,
2^n=128,
=>2^n=2^7,
=>n=7,
Hence we require 7 flipflops.
2^n=128,
=>2^n=2^7,
=>n=7,
Hence we require 7 flipflops.
Puja said:
1 decade ago
No.of flip flops = 2^n.
According that formula 2^7=128 is correct.
So, required flip flop is 7.
According that formula 2^7=128 is correct.
So, required flip flop is 7.
Abubakar maliki said:
1 decade ago
Even if we take 2>7 it will still give 128 so the flip-flops required are 7.
Saieswari said:
8 years ago
How many flip flops are needed to divide the input frequency by 64 device?
(1)
Ranjitha v said:
8 years ago
I think 7. This is no series count value of (1 2 4 8 16 32 64) -2^7=64.
Vipul Prajapati said:
9 years ago
Correct, but if there is suppose 10 then what will be the answer?
Csk said:
1 decade ago
128 equal to 2 power n where n is the number of flip flops.....
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