Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 3 (Q.No. 1)
Directions to Solve
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
| Student | Subject (Max. Marks) | |||||
| Maths | Chemistry | Physics | Geography | History | Computer Science | |
| (150) | (130) | (120) | (100) | (60) | (40) | |
| Ayush | 90 | 50 | 90 | 60 | 70 | 80 |
| Aman | 100 | 80 | 80 | 40 | 80 | 70 |
| Sajal | 90 | 60 | 70 | 70 | 90 | 70 |
| Rohit | 80 | 65 | 80 | 80 | 60 | 60 |
| Muskan | 80 | 65 | 85 | 95 | 50 | 90 |
| Tanvi | 70 | 75 | 65 | 85 | 40 | 60 |
| Tarun | 65 | 35 | 50 | 77 | 80 | 80 |
1.
What are the average marks obtained by all the seven students in Physics? (rounded off to two digit after decimal)
Answer: Option
Explanation:
Average marks obtained in Physics by all the seven students
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| + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ] | |||||
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| = 89.14. |
Discussion:
49 comments Page 1 of 5.
Rajat said:
5 years ago
As in question, we are having the percentage of marks not the marks of the subjects, therefore, we are doing.
[(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120)]
Here,
1/7x [(90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120].
we have taken the 120 as common and afterwards, we found our solution.
[(90% of 120) + (80% of 120) + (70% of 120) + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120)]
Here,
1/7x [(90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120].
we have taken the 120 as common and afterwards, we found our solution.
Anurag said:
9 years ago
Two ways:
Either calculate the individual marks according to the percentage of marks given in the table. Then add all the marks and divide it by 7 to find out the Average marks.
Or
Do the sumtotal of all the percentage and then calculate the total marks for all the student and then divide by 7 to get the average marks.
Thanks.
Either calculate the individual marks according to the percentage of marks given in the table. Then add all the marks and divide it by 7 to find out the Average marks.
Or
Do the sumtotal of all the percentage and then calculate the total marks for all the student and then divide by 7 to get the average marks.
Thanks.
Mayur Dhamankar said:
9 years ago
Thanks Everyone It clear my Doubt.
1/7 x [(90% of120) +(80% of120) +(70% of120)+(80% of120) + (85% of120) + (65%of120) + (50% of120)].
=1/7x(90+80+70+80+85+65+50)% of 120].
=1/7x [ 520% of 120 ] i.e 1/7 * [520/100*120].
1/7*[52*12] = 624/7.
= 89.14.
1/7 x [(90% of120) +(80% of120) +(70% of120)+(80% of120) + (85% of120) + (65%of120) + (50% of120)].
=1/7x(90+80+70+80+85+65+50)% of 120].
=1/7x [ 520% of 120 ] i.e 1/7 * [520/100*120].
1/7*[52*12] = 624/7.
= 89.14.
Fareen Khan said:
7 years ago
Because the actual marks obtained by students are not given, marks are given in (%) and Ayush got 90 (%) marks out of 120 marks.
So we need to calculate 90(%) of 120 to get the marks obtained by Ayush in physics.
So we need to calculate 90(%) of 120 to get the marks obtained by Ayush in physics.
Samsam said:
6 years ago
@Akshata.
It's written 'percentage of marks' not just marks and yes 90% of 120 is not 90 but they have taken " % of 120" as common and grouped the percentage marks together for addition in the second step.
It's written 'percentage of marks' not just marks and yes 90% of 120 is not 90 but they have taken " % of 120" as common and grouped the percentage marks together for addition in the second step.
Saurabh gupta said:
6 years ago
@All.
There is a big mistake in the question. That is, all the marks obtained by a student (Not the marks percentage) but in the answer, they are using them as percentage marks! How? Explain me clearly.
There is a big mistake in the question. That is, all the marks obtained by a student (Not the marks percentage) but in the answer, they are using them as percentage marks! How? Explain me clearly.
Lalitha said:
2 years ago
As they have given the percentage of marks, we need to calculate the actual marks, so 90% means, 90/100 (120). From this, we get the actual marks scored.
Correct me, If my concept is wrong.
Correct me, If my concept is wrong.
Deki said:
2 years ago
It's simple.
You can add all the marks obtained in physics by 7students, you will get 520 of 120.
Here of 120 mean: result/100 * total mark.
120/100 * 520 = 624
624/7 = 89.14.
You can add all the marks obtained in physics by 7students, you will get 520 of 120.
Here of 120 mean: result/100 * total mark.
120/100 * 520 = 624
624/7 = 89.14.
(2)
DEVARAJU said:
10 years ago
We are taking only marks here. Why we have to take % here.
Actually marks are given of all students so, We calculate only avg of marks.
Sol: Total marks is 520/7 = 74.29.
Actually marks are given of all students so, We calculate only avg of marks.
Sol: Total marks is 520/7 = 74.29.
Reshma pawar said:
9 years ago
Yes @Namit you are right. So for calculating average, first we have to find the marks obtained by each student out of max. Marks and then add all marks and divide by 7.
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