Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 3 (Q.No. 1)
Directions to Solve
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
| Student | Subject (Max. Marks) | |||||
| Maths | Chemistry | Physics | Geography | History | Computer Science | |
| (150) | (130) | (120) | (100) | (60) | (40) | |
| Ayush | 90 | 50 | 90 | 60 | 70 | 80 |
| Aman | 100 | 80 | 80 | 40 | 80 | 70 |
| Sajal | 90 | 60 | 70 | 70 | 90 | 70 |
| Rohit | 80 | 65 | 80 | 80 | 60 | 60 |
| Muskan | 80 | 65 | 85 | 95 | 50 | 90 |
| Tanvi | 70 | 75 | 65 | 85 | 40 | 60 |
| Tarun | 65 | 35 | 50 | 77 | 80 | 80 |
1.
What are the average marks obtained by all the seven students in Physics? (rounded off to two digit after decimal)
Answer: Option
Explanation:
Average marks obtained in Physics by all the seven students
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| + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ] | |||||
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| = 89.14. |
Discussion:
51 comments Page 2 of 6.
Manojkumar.v said:
7 years ago
As per my solution;
First, l am calculating to the total % in physics 120% total marks 7.
(90+80+70+80+85+65+50)/7 * 120 = 520/7 * 120 = 74.3 * 120 = 89.16.
First, l am calculating to the total % in physics 120% total marks 7.
(90+80+70+80+85+65+50)/7 * 120 = 520/7 * 120 = 74.3 * 120 = 89.16.
(1)
Sanjay Kumar said:
9 years ago
In question, it is not given anywhere that the marks are in %. Maximum marks (Subject) is only mentioned. So the solution must be 520/7 = 74.28.
Christine said:
1 decade ago
Thanks guys. It clear my doubt. I didn't understand at first and after reading your post I came to know the reason. I really appreciate it.
Lakshmi said:
10 years ago
I am replying for the previous comment, I am in small confusion of (%) sorry for that comment so the right answer is 89.14.
Milan Pipaliya said:
5 years ago
In Computer Science Max Mark is 40, But Student Marks is given up to 90. How can we get 90 marks even Max mark is 40 only.
(1)
Mark gor said:
8 years ago
We can 1/7 * (90+80+70+80+85+65+50).
= 1/7 * 520.
= 74.2857 * 1.2 (full mark 120%) = 89.14.
= 1/7 * 520.
= 74.2857 * 1.2 (full mark 120%) = 89.14.
Shashank Rawat said:
9 years ago
How can it be possible, max marks of history & com-science are less than the marks obtained by the students?
Pavan W. said:
7 years ago
Easy way:-
((Total Marks)/(No. of Students))*(outoff marks).
i.e. (520/7)*120 = 89.14.
[520*120]/7 =86.14.
((Total Marks)/(No. of Students))*(outoff marks).
i.e. (520/7)*120 = 89.14.
[520*120]/7 =86.14.
Mouni said:
8 years ago
Simple= 520/100*120=624.
You can try to first divisible get 0 or canceled and got multiply 12*52=624.
You can try to first divisible get 0 or canceled and got multiply 12*52=624.
Kumaraswamy said:
1 decade ago
@Neharika:
All above total markes same, so per add 120 is common
a%150 + b%150 + c%150=(a +b +c)%150
All above total markes same, so per add 120 is common
a%150 + b%150 + c%150=(a +b +c)%150
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