# Data Interpretation - Table Charts - Discussion

Discussion Forum : Table Charts - Table Chart 3 (Q.No. 1)
Directions to Solve

The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.

The Numbers in the Brackets give the Maximum Marks in Each Subject.

 Student Subject (Max. Marks) Maths Chemistry Physics Geography History Computer Science (150) (130) (120) (100) (60) (40) Ayush 90 50 90 60 70 80 Aman 100 80 80 40 80 70 Sajal 90 60 70 70 90 70 Rohit 80 65 80 80 60 60 Muskan 80 65 85 95 50 90 Tanvi 70 75 65 85 40 60 Tarun 65 35 50 77 80 80

1.
What are the average marks obtained by all the seven students in Physics? (rounded off to two digit after decimal)
77.26
89.14
91.37
96.11
Explanation:

Average marks obtained in Physics by all the seven students

 = 1 x [ (90% of 120) + (80% of 120) + (70% of 120) 7
+ (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ]
 = 1 x [ (90 + 80 + 70 + 80 + 85 + 65 + 50)% of 120 ] 7
 = 1 x [ 520% of 120 ] 7
 = 624 7
= 89.14.

Discussion:
49 comments Page 1 of 5.

Why are we taking 520% of 120 here?

Because in the table % of marks obtained in each subjects are mentioned.

Why are we taking 624/7 ?

Why we took percentage of all?

Why we are taking 624?

@Neharika:

All above total markes same, so per add 120 is common

a%150 + b%150 + c%150=(a +b +c)%150

How we got 624?

@Sam

(90+80+70+80+85+65+50/100)*120 = ((520)/100)*120 = 52*12 = 624