Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 3 (Q.No. 1)
Directions to Solve
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
| Student | Subject (Max. Marks) | |||||
| Maths | Chemistry | Physics | Geography | History | Computer Science | |
| (150) | (130) | (120) | (100) | (60) | (40) | |
| Ayush | 90 | 50 | 90 | 60 | 70 | 80 |
| Aman | 100 | 80 | 80 | 40 | 80 | 70 |
| Sajal | 90 | 60 | 70 | 70 | 90 | 70 |
| Rohit | 80 | 65 | 80 | 80 | 60 | 60 |
| Muskan | 80 | 65 | 85 | 95 | 50 | 90 |
| Tanvi | 70 | 75 | 65 | 85 | 40 | 60 |
| Tarun | 65 | 35 | 50 | 77 | 80 | 80 |
1.
What are the average marks obtained by all the seven students in Physics? (rounded off to two digit after decimal)
Answer: Option
Explanation:
Average marks obtained in Physics by all the seven students
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| + (80% of 120) + (85% of 120) + (65% of 120) + (50% of 120) ] | |||||
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| = 89.14. |
Discussion:
49 comments Page 1 of 5.
Neharika said:
1 decade ago
Why are we taking 520% of 120 here?
Asd said:
1 decade ago
Because in the table % of marks obtained in each subjects are mentioned.
Ravindersingh said:
1 decade ago
Why are we taking 624/7 ?
Sanchita said:
1 decade ago
Why we took percentage of all?
Rajkishore said:
1 decade ago
Why we are taking 624?
Kumaraswamy said:
1 decade ago
@Neharika:
All above total markes same, so per add 120 is common
a%150 + b%150 + c%150=(a +b +c)%150
All above total markes same, so per add 120 is common
a%150 + b%150 + c%150=(a +b +c)%150
Sam said:
1 decade ago
How we got 624?
Sekar said:
1 decade ago
@Sam
(90+80+70+80+85+65+50/100)*120 = ((520)/100)*120 = 52*12 = 624
(90+80+70+80+85+65+50/100)*120 = ((520)/100)*120 = 52*12 = 624
Krishna said:
1 decade ago
Why we are calculating % over here? means in order to find avg we just sum all the number/total num.
Sami said:
10 years ago
Why we are taking 1/7 here?
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