Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 2 (Q.No. 3)
Directions to Solve
Study the following table and answer the questions.
Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.
| State | Year | |||||||||
| 1997 | 1998 | 1999 | 2000 | 2001 | ||||||
| App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | |
| M | 5200 | 720 | 8500 | 980 | 7400 | 850 | 6800 | 775 | 9500 | 1125 |
| N | 7500 | 840 | 9200 | 1050 | 8450 | 920 | 9200 | 980 | 8800 | 1020 |
| P | 6400 | 780 | 8800 | 1020 | 7800 | 890 | 8750 | 1010 | 9750 | 1250 |
| Q | 8100 | 950 | 9500 | 1240 | 8700 | 980 | 9700 | 1200 | 8950 | 995 |
| R | 7800 | 870 | 7600 | 940 | 9800 | 1350 | 7600 | 945 | 7990 | 885 |
3.
In which of the given years the number of candidates appeared from State P has maximum percentage of qualified candidates?
Answer: Option
Explanation:
The percentages of candidates qualified to candidates appeared from State P during different years are:
| For 1997 |  |
780 | x 100 |  |
% = 12.19%. |
| 6400 |
| For 1998 | |
1020 | x 100 | |
% = 11.59%. |
| 8800 |
| For 1999 | |
890 | x 100 | |
% = 11.41%. |
| 7800 |
| For 2000 | |
1010 | x 100 | |
% = 11.54%. |
| 8750 |
| For 2001 | |
1250 | x 100 | |
% = 12.82%. |
| 9750 |
Maximum percentage is for the year 2001.
Discussion:
19 comments Page 1 of 2.
Rakesh said:
1 decade ago
I think taking difference will not work all the time.
Reason: consider case 1: applied 5 and qualified 1. difference is (5-1) = 4.
Case 2: applied 10 and qualified 7 difference is (10-7) = 3.
Now, as per above logic since case 1 difference value is more we expect case 1 percentage as higher but in reality case 1 percent is 1/5 = 2/10 = 200/10% = 20%.
And case 2 is 7/10 = 700/10% = 70%.
Clearly, case 2 is higher :-(.
Reason: consider case 1: applied 5 and qualified 1. difference is (5-1) = 4.
Case 2: applied 10 and qualified 7 difference is (10-7) = 3.
Now, as per above logic since case 1 difference value is more we expect case 1 percentage as higher but in reality case 1 percent is 1/5 = 2/10 = 200/10% = 20%.
And case 2 is 7/10 = 700/10% = 70%.
Clearly, case 2 is higher :-(.
Gopal said:
4 years ago
The answer would be in approximation terms(to the nearest round off number, 100 multiple)
Then compare the fraction value;
1997------>6400(800) --> 1/8,
1998------>8800(1000) --> 1/8.8(approx 1/9),
1999------>7800(900)--> 1/8.7,
2000------>8800(1000)--> 1/8.8(approx 1/9),
2001------>9800(1300)-->1/7.5.
So, less denominator value in 2001. So this is the possible answer.
Then compare the fraction value;
1997------>6400(800) --> 1/8,
1998------>8800(1000) --> 1/8.8(approx 1/9),
1999------>7800(900)--> 1/8.7,
2000------>8800(1000)--> 1/8.8(approx 1/9),
2001------>9800(1300)-->1/7.5.
So, less denominator value in 2001. So this is the possible answer.
(8)
Ankita Thakur said:
5 years ago
I think we can do round off of all the figures.
In multiples of 100; Like;
780/6400*100 = 80000/6400 = 12%apporx.
1020/8800*100 =100000/9000,
890/7800*100 = 90000/8000,
1010/8750*100 =100000/9000,
1250/9750*100 =130000/10000 = 13%approx.
Answer Will be 2001(D).
In multiples of 100; Like;
780/6400*100 = 80000/6400 = 12%apporx.
1020/8800*100 =100000/9000,
890/7800*100 = 90000/8000,
1010/8750*100 =100000/9000,
1250/9750*100 =130000/10000 = 13%approx.
Answer Will be 2001(D).
(2)
PRAVEEN said:
1 decade ago
Find the maximum percentage right.
Take the difference between appeared and qualified.
1997------>5620.
1998------>7780.
1999------>6910.
2000------>7740.
2001------>8500.
So difference high in 2001. So that is answer.
Take the difference between appeared and qualified.
1997------>5620.
1998------>7780.
1999------>6910.
2000------>7740.
2001------>8500.
So difference high in 2001. So that is answer.
Joh said:
1 decade ago
Dear @Praveen as per your idea its good, but after 2001 immediate high difference will be as per your idea 7780(in 1998) , but as per solving entire problem it is coming 1997, how come it can apply for all the problems? please justify.
SHIVANGI GUPTA said:
9 years ago
I read all the above comments, so basically there is no other way to find out the highest percentage other than to just calculate. As observations turn out to be right only in sometimes.
Karthi said:
7 years ago
@Praveen.
Your answer is correct.
One thing to note is that we are getting total failed by subtracting. So the least failed is high pass percentage.
Your answer is correct.
One thing to note is that we are getting total failed by subtracting. So the least failed is high pass percentage.
Chaitali said:
1 decade ago
Well we can use the formula:.
Final value-original value/original value.
Final value will be current year.
Original value will be previous year.
Final value-original value/original value.
Final value will be current year.
Original value will be previous year.
Suresh kumar said:
9 years ago
@Merina.
Which is having the highest denominator, that percentage take a maximum. i.e 9750 is highest dmnatr so it maximum.
Which is having the highest denominator, that percentage take a maximum. i.e 9750 is highest dmnatr so it maximum.
(1)
Aman said:
1 decade ago
Yup just compare all the Qualified figures with each other you'll get maximum qualified candidates in 2001.
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