Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 2 (Q.No. 3)
Directions to Solve
Study the following table and answer the questions.
Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.
| State | Year | |||||||||
| 1997 | 1998 | 1999 | 2000 | 2001 | ||||||
| App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | |
| M | 5200 | 720 | 8500 | 980 | 7400 | 850 | 6800 | 775 | 9500 | 1125 |
| N | 7500 | 840 | 9200 | 1050 | 8450 | 920 | 9200 | 980 | 8800 | 1020 |
| P | 6400 | 780 | 8800 | 1020 | 7800 | 890 | 8750 | 1010 | 9750 | 1250 |
| Q | 8100 | 950 | 9500 | 1240 | 8700 | 980 | 9700 | 1200 | 8950 | 995 |
| R | 7800 | 870 | 7600 | 940 | 9800 | 1350 | 7600 | 945 | 7990 | 885 |
3.
In which of the given years the number of candidates appeared from State P has maximum percentage of qualified candidates?
Answer: Option
Explanation:
The percentages of candidates qualified to candidates appeared from State P during different years are:
| For 1997 |  |
780 | x 100 |  |
% = 12.19%. |
| 6400 |
| For 1998 | |
1020 | x 100 | |
% = 11.59%. |
| 8800 |
| For 1999 | |
890 | x 100 | |
% = 11.41%. |
| 7800 |
| For 2000 | |
1010 | x 100 | |
% = 11.54%. |
| 8750 |
| For 2001 | |
1250 | x 100 | |
% = 12.82%. |
| 9750 |
Maximum percentage is for the year 2001.
Discussion:
19 comments Page 1 of 2.
Gopal said:
4 years ago
The answer would be in approximation terms(to the nearest round off number, 100 multiple)
Then compare the fraction value;
1997------>6400(800) --> 1/8,
1998------>8800(1000) --> 1/8.8(approx 1/9),
1999------>7800(900)--> 1/8.7,
2000------>8800(1000)--> 1/8.8(approx 1/9),
2001------>9800(1300)-->1/7.5.
So, less denominator value in 2001. So this is the possible answer.
Then compare the fraction value;
1997------>6400(800) --> 1/8,
1998------>8800(1000) --> 1/8.8(approx 1/9),
1999------>7800(900)--> 1/8.7,
2000------>8800(1000)--> 1/8.8(approx 1/9),
2001------>9800(1300)-->1/7.5.
So, less denominator value in 2001. So this is the possible answer.
(8)
Ankita Thakur said:
5 years ago
I think we can do round off of all the figures.
In multiples of 100; Like;
780/6400*100 = 80000/6400 = 12%apporx.
1020/8800*100 =100000/9000,
890/7800*100 = 90000/8000,
1010/8750*100 =100000/9000,
1250/9750*100 =130000/10000 = 13%approx.
Answer Will be 2001(D).
In multiples of 100; Like;
780/6400*100 = 80000/6400 = 12%apporx.
1020/8800*100 =100000/9000,
890/7800*100 = 90000/8000,
1010/8750*100 =100000/9000,
1250/9750*100 =130000/10000 = 13%approx.
Answer Will be 2001(D).
(2)
Nai said:
6 years ago
I think it should be appear/qualified but why they put qualified/appear? Could anyone explain me this?
(1)
Suresh kumar said:
9 years ago
@Merina.
Which is having the highest denominator, that percentage take a maximum. i.e 9750 is highest dmnatr so it maximum.
Which is having the highest denominator, that percentage take a maximum. i.e 9750 is highest dmnatr so it maximum.
(1)
Jithin said:
9 years ago
@Tara.
It is not correct. If the denominator is also high percentage will be less.
It is not correct. If the denominator is also high percentage will be less.
Patel said:
4 years ago
Very good, Thanks @Gopal.
Karthi said:
7 years ago
@Praveen.
Your answer is correct.
One thing to note is that we are getting total failed by subtracting. So the least failed is high pass percentage.
Your answer is correct.
One thing to note is that we are getting total failed by subtracting. So the least failed is high pass percentage.
Rudraksh Barnwal said:
8 years ago
We can solve this question by -appear/qualify*100.
S j prakash said:
9 years ago
How to calculate the percentage? Please guide me.
SHIVANGI GUPTA said:
9 years ago
I read all the above comments, so basically there is no other way to find out the highest percentage other than to just calculate. As observations turn out to be right only in sometimes.
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