Data Interpretation - Table Charts - Discussion
Discussion Forum : Table Charts - Table Chart 2 (Q.No. 3)
Directions to Solve
Study the following table and answer the questions.
Number of Candidates Appeared and Qualified in a Competitive Examination from Different States Over the Years.
| State | Year | |||||||||
| 1997 | 1998 | 1999 | 2000 | 2001 | ||||||
| App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | App. | Qual. | |
| M | 5200 | 720 | 8500 | 980 | 7400 | 850 | 6800 | 775 | 9500 | 1125 |
| N | 7500 | 840 | 9200 | 1050 | 8450 | 920 | 9200 | 980 | 8800 | 1020 |
| P | 6400 | 780 | 8800 | 1020 | 7800 | 890 | 8750 | 1010 | 9750 | 1250 |
| Q | 8100 | 950 | 9500 | 1240 | 8700 | 980 | 9700 | 1200 | 8950 | 995 |
| R | 7800 | 870 | 7600 | 940 | 9800 | 1350 | 7600 | 945 | 7990 | 885 |
3.
In which of the given years the number of candidates appeared from State P has maximum percentage of qualified candidates?
Answer: Option
Explanation:
The percentages of candidates qualified to candidates appeared from State P during different years are:
| For 1997 |  |
780 | x 100 |  |
% = 12.19%. |
| 6400 |
| For 1998 | |
1020 | x 100 | |
% = 11.59%. |
| 8800 |
| For 1999 | |
890 | x 100 | |
% = 11.41%. |
| 7800 |
| For 2000 | |
1010 | x 100 | |
% = 11.54%. |
| 8750 |
| For 2001 | |
1250 | x 100 | |
% = 12.82%. |
| 9750 |
Maximum percentage is for the year 2001.
Discussion:
19 comments Page 1 of 2.
Merina said:
1 decade ago
Is there an easier to find out the solution without doing the entire calculation??
Aman said:
1 decade ago
Yup just compare all the Qualified figures with each other you'll get maximum qualified candidates in 2001.
PRAVEEN said:
1 decade ago
Find the maximum percentage right.
Take the difference between appeared and qualified.
1997------>5620.
1998------>7780.
1999------>6910.
2000------>7740.
2001------>8500.
So difference high in 2001. So that is answer.
Take the difference between appeared and qualified.
1997------>5620.
1998------>7780.
1999------>6910.
2000------>7740.
2001------>8500.
So difference high in 2001. So that is answer.
Prabha said:
1 decade ago
Thanks praveen. The way you explained is the most simplest.
Ritesh said:
1 decade ago
@Praveen is it applicable on all similar questions.
Joh said:
1 decade ago
Dear @Praveen as per your idea its good, but after 2001 immediate high difference will be as per your idea 7780(in 1998) , but as per solving entire problem it is coming 1997, how come it can apply for all the problems? please justify.
Rakesh said:
1 decade ago
I think taking difference will not work all the time.
Reason: consider case 1: applied 5 and qualified 1. difference is (5-1) = 4.
Case 2: applied 10 and qualified 7 difference is (10-7) = 3.
Now, as per above logic since case 1 difference value is more we expect case 1 percentage as higher but in reality case 1 percent is 1/5 = 2/10 = 200/10% = 20%.
And case 2 is 7/10 = 700/10% = 70%.
Clearly, case 2 is higher :-(.
Reason: consider case 1: applied 5 and qualified 1. difference is (5-1) = 4.
Case 2: applied 10 and qualified 7 difference is (10-7) = 3.
Now, as per above logic since case 1 difference value is more we expect case 1 percentage as higher but in reality case 1 percent is 1/5 = 2/10 = 200/10% = 20%.
And case 2 is 7/10 = 700/10% = 70%.
Clearly, case 2 is higher :-(.
Chaitali said:
1 decade ago
Well we can use the formula:.
Final value-original value/original value.
Final value will be current year.
Original value will be previous year.
Final value-original value/original value.
Final value will be current year.
Original value will be previous year.
Tara said:
9 years ago
Just see the highest figure of qualified candidates from state P in all the years.
Jithin said:
9 years ago
@Tara.
It is not correct. If the denominator is also high percentage will be less.
It is not correct. If the denominator is also high percentage will be less.
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